Question

49 080 tickets have been sold for the tournament. 3 /5 of the tickets are for the qualifying matches and 15% of the tickets are for the final match. How many tickets sold are for the semi-final matches

Answer 1

The answer is 10,270. 3/5 of 49,080 is 29448 and 15% of 49,080 is 7362. 29448+7362 is 36810 and 49080-36810=10270.

Answer 2

Answer:  The required number of tickets sold for the semi-final matches is 12270.

Step-by-step explanation:  Given that 49080 tickets have been sold for the tournament. $\dfrac{3}{5}$ of the tickets are for the qualifying matches and 15% of the tickets are for the final match.

We are to find the number of tickets that sold for the semi-final matches.

Let s denotes the number of tickets that are sold for semi final matches.

According to the given information, we have

Number of tickets sold for the qualifying matches is

$n_q=\dfrac{3}{5}\times49080=29448$

and the number of tickets sold for the final match is

$n_f=15\%\times49080=\dfrac{15}{100}\times49080=7362.$

Therefore, we must have

$n_q+n_f+s=49080\\\\\Rightarrow 29448+7362+s=49080\\\\\Rightarrow 36810+s=49080\\\\\Rightarrow s=49080-36810\\\\\Rightarrow s=12270.$

Thus, the required number of tickets sold for the semi-final matches is 12270.