Answer:
Step-by-step explanation:
We are given that,
The fall of the acorn is represented by the function,
Equating S(t) to 0 gives,
i.e.
i.e.
i.e.
Since, time cannot be negative.
So, i.e. 1.25 seconds is the time when the acorn will reach the ground.
Thus, from the figure below, we see that,
The interval in which the acorn is in the moving air is .
Answer:
Step-by-step explanation:
In rectangle ABCD, AB = 6, BC = 8, and DE = DF.
ΔDEF is one-fourth the area of rectangle ABCD.
We want to determine the length of EF.
First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:
The area of the triangle is 1/4 of this. Therefore:
The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:
Since DE = DF:
Thus:
Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:
Therefore:
Square:
Add:
And finally, we can take the square root of both sides:
Answer:
In every 42 days, Sherman and Brad will go golfing on the same day.
Step-by-step explanation:
Given:
Sherman goes golfing every 6th day.
Brad goes golfing every 7th day.
If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.
Solution:
In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.
To find least common multiple of 6 and 7, we will list out their multiples.
We find out that the least common multiple of 6 and 7 =42.
Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..