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vlabodo [156]
3 years ago
11

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
ELEN [110]3 years ago
5 0

Answer:

B. False; to be concave the angles cannot be congruent.

Step-by-step explanation:

Regular Polygons are never concave.

enyata [817]3 years ago
3 0

Answer:

The answer is B

Step-by-step explanation:

In order for a polygon to be regular, all angles <u>must be congruent</u>.

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I need help factoring this expression
omeli [17]
X^2(x+2)-4(x+2)

(x^2-4) (x+2) = 0

do you have to keep going/?

or thats all they want?
3 0
3 years ago
Jessica earned $16 mowing a neighbor's yard. She bought a craft kit for $7.37. She used $3.75 to buy food for a food drive. She
iogann1982 [59]

Answer:

$4.88

Step-by-step explanation:

Jessica made $16 mowing a neighbors yard

She brought a craft kit for $7.37

16-7.37

= 8.63

She used $3.75 to buy food for a food drive

8.63-3.75

= 4.88

Hence the amount Jessica put in the savings account is $4.88

4 0
2 years ago
Read 2 more answers
If f(x)=3x and g(x)=1/x, what is the domain of (g o f)(x)?
Neko [114]

Here it is given that f(x)=3x and g(x)=1/x

We have to find the domain of (g o f)(x)

Now it is given that f(x) = 3x

and it is also given that g(x) = 1/x

so (g o f)(x) = g( f(x) ) = g( 3x )

which comes out to be 1 / 3x

The domain of the expression is all the real numbers except where the expression is undefined so the domain of the given expression is all real numbers except 0.

5 0
2 years ago
The population mean annual salary for environmental compliance specialists is about ​$62,000. A random sample of 32 specialists
lakkis [162]

Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about ​$62,000.

i.e. \mu=62000  

Sample size : n= 32

\sigma=6200

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 59000 will be :

z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than ​$59,000 :-

P(z

Hence, the probability that the mean salary of the sample is less than ​$59,000= 0.002718

3 0
3 years ago
Any one like polynomials?
GREYUIT [131]

Answer:

2o.x that the anwers shs

6 0
3 years ago
Read 2 more answers
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