Answer:
The pebble will hit the ground 8.29 second after it is thrown.
Step-by-step explanation:
Given that,
The height of the pebble after t seconds is given by the equation
h= -16t²+24 t+900.
When the pebble hit the ground, the height of the pebble will be zero.
So putting h=0 in the given equation.
0 = -16t²+24 t+900
⇒-4(4t²-6t-225)=0
⇒4t²-6t-225=0
Applying quadratic formula 
, here a=4, b= -6 and c= -225.
⇒ t = 8.29, -6.79
Since time can not negative.
∴t=8.29 seconds.
The pebble will hit the ground 8.29 second after it is thrown.
Answer:
Step-by-step explanation:
(4+1)/(8-2)= 5/6
y + 1 = 5/6(x - 2)
y + 1 = 5/6x - 5/3
y + 3/3 = 5/6x - 5/3
y = 5/6x - 8/3
6(y = 5/6x - 8/3)
6y = 5x - 16
-5x + 6y = -16
You can set up a simple algebraic equivalent to find a number equivalent to 200 after being multiplied by 3 and added 11 to.
3x+11=200
3x=189
x=63
Had to edit! Realized what I had done wrong
Step-by-step explanation:
<h3> new numbers are x+4 and x-1</h3>
so, x+4/x-1=11/16
16x+64=11x-11
16x-11x=-11-64
5x=-75
x = -15
also, x+1 = -14
Answer:
0+100 1+1000 2+2000 3+3000
Step-by-step explanation:
