Answer:
576.6
Step-by-step explanation:
Answer:
A. Area under a curve
Step-by-step explanation:
Edge 2021
Yes initial amount is 2044 (in millions)
Since the function is from 2000 then you can set it up as
B(t)=2044*a^t
To solve for "a" use the second number given, 3846, and since this value is 5 years after 2000 t=5
so we plug in these values
3846=2044*a^5
we now solve for a
first, divide by 2044
3846/2044=a^5
next, we take the 5th root
<span>5sqrt(3846/2044) = a
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</span>
Since the multiplication between two matrices is not <em>commutative</em>, then
, regardless of the dimensions of
.
<h3>Is the product of two matrices commutative?</h3>
In linear algebra, we define the product of two matrices as follows:
, where
,
and
(1)
Where each element of the matrix is equal to the following dot product:
, where 1 ≤ i ≤ m and 1 ≤ j ≤ n. (2)
Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not <em>commutative</em> because of the nature and characteristics of the definition itself, which implies operating on a row of the <em>former</em> matrix and a column of the <em>latter</em> matrix.
Such <em>"arbitrariness"</em> means that <em>resulting</em> value for
will be different if the order between
and
is changed and even the dimensions of
may be different. Therefore, the proposition is false.
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