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Viktor [21]
3 years ago
11

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

erscript negative 12 Baseline q Superscript negative 3 Baseline EndFraction in simplified form? Assume p not-equals 0, q not-equals 0.
Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

-\frac{3p^8}{4q^3}

Step-by-step explanation:

\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}  can be broken down into three fractions, coefficients, powers of p, powers of q.

-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}

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Brian ate 1/5 of a pie. The colin ate 1/5 of the pie, and david ate 1/5 of the pie.
sleet_krkn [62]

Answer:

2/5

Step-by-step explanation:

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3 years ago
Four football fans took turns driving the distance from new York to Oklahoma to see a big game
Snezhnost [94]
I'm sorry but what's the full question?
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4 years ago
Given: Line A R bisects ∠BAC; AB = AC
Nadya [2.5K]

The ΔABR ≅ ΔACR are congruent by SAS theorem

Option D is the correct answer.

The missing diagram is attched with the answer.

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices and three angles.

SAS will be used to prove the congruence of ΔABR ≅ ΔACR

In both the triangle we have a common side , AR

AB = AC (given)

∠ B A R =  ∠R A C ( given equal)

So as the two side and the included angle is equal

Therefore the ΔABR ≅ ΔACR are congruent by SAS theorem

Option D is the correct answer.

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8 0
2 years ago
Which expression represents 10 times the sum of 2 and 1?
sergeinik [125]
The expression would be

10(2+1)

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7 0
3 years ago
Read 2 more answers
A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1200 hours and a standar
a_sh-v [17]

Answer:

The bulbs should be replaced each 1060.5 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1200, \sigma = 60

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.

Z = \frac{X - \mu}{\sigma}

-2.325 = \frac{X - 1200}{60}

X - 1200 = -2.325*60

X = 1060.5

The bulbs should be replaced each 1060.5 days.

4 0
3 years ago
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