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wolverine [178]
3 years ago
7

Find the Area? length is 9m and width 4m​

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

9*4=36

I did the math

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Find x helpppppppppppp​
lidiya [134]

|2x - 1|  =  | - x - 2|

Thus ;

2x - 1 =  - x - 2

Add both sides x

2x + x - 1 =  - x + x - 2

3x - 1 =  - 2

Add both sides 1

3x - 1 + 1 =  - 2 + 1

3x =   - 1

Divide both sides by 3

\frac{3x}{3}  =  \frac{ - 1}{3}  \\

x =  -  \frac{1}{3}  \\

<h2>Or </h2>

2x - 1 =  - ( - x - 2)

2x - 1 = x + 2

Subtract both sides x

2x  - x  - 1 = x - x + 2

x - 1 = 2

Add both sides 1

x - 1 + 1 = 2 + 1

x = 3

There u go ...

3 0
2 years ago
A force of 10 newtons act in a direction 75 above horizontal moving an object 15 meters from (0,0) to (15,0). What is the work d
givi [52]

Answer:

C

Step-by-step explanation:

i think

4 0
3 years ago
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{(−1, 5), (2, 8), (5, 3), (13, −4)} what are the range
makkiz [27]
(x;\ y)\\\\(-1, \fbox5), (2, \fbox8), (5, \fbox3), (13, \fbox{-4})\\\\\boxed{The\ range:y\in\{-4;\ 3;\ 5;\ 8\}}
7 0
3 years ago
victor went for a run last week. It was 3.5 km long. Terrell went for 3 runs last week. eachrun was 1,250 m long. which person r
Karolina [17]
Terrell ran a longer distance
7 0
3 years ago
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What is the value of x in the equation x - y = 30, when y = 15?<br> O4<br> O 8<br> O 80<br> O 200
olganol [36]

\frac{1}{5}x -  \frac{2}{3} y = 30  \\

Putting the value of Y = 15

\frac{1}{5} x -  \frac{2}{3}  \times 15 = 30  \\   \frac{1}{5} x = 30  +  10 \\  \frac{1}{5} x = 40 \\ x = 5 \times 40 \\  x = 200

So, X = 200

6 0
2 years ago
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