We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Answer:
434.9
Step-by-step explanation:
The circumference is 29.53.
Hope that this helps!
He should change the coefficient 5
Answer:
x=45
Step-by-step explanation:
2x+45+x=180
Combine 2x and x to get 3x.
3x+45=180
Subtract 45 from both sides.
3x=180−45
Subtract 45 from 180 to get 135.
3x=135
Divide both sides by 3.
x=135/3
Divide 135 by 3
x=45
To convert a quadratic<span> from y = ax</span>2<span> + bx + c form to </span>vertex<span> form, y = a(x - h)</span>2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2<span>- 4x + 5 into </span>vertex<span> form, and state the </span>vertex<span>.</span>
