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olganol [36]
3 years ago
7

Pls help or your mom will kidnap you

Mathematics
2 answers:
patriot [66]3 years ago
4 0
I think this answer might be number 1 as well
andrey2020 [161]3 years ago
3 0
I think it is option 1 sorry if wrong
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Find the area of rectangle ABCD
salantis [7]

Answer: 12

Step-by-step explanation:

You can find the area of a rectangle that forms around it, and then subtract the little extra triangles. You can form a 5 by 5 square around the points. There are 4 extra little triangles. Two of them have a base and height of 2 and 2. Two of them have a base and height of 3 and 3. So you get the total area of those 4 triangles to be: 2+2+4.5+4.5=13. So 25-13=12.

7 0
3 years ago
Let f(x) = - 10x + 9 and g(x) = x2 + 12 <br>Find f( - 4)/g( - 4)​
Reptile [31]

Answer:

\frac{49}{28}

Step-by-step explanation:

Evaluate g(- 4) and f(- 4) by substituting x = - 4 into g(x) and f(x), that is

f(- 4) = - 10(- 4) + 9 = 40 + 9 = 49

g(- 4) = (- 4)² + 12 = 16 + 12 = 28

Then

\frac{f(-4)}{g(-4)} = \frac{49}{28} = \frac{7}{4}

7 0
4 years ago
Russ walks 710 mile to school. How far has he walked when he has covered 58 of the distance to school?\
zloy xaker [14]

Answer: \frac{7}{16}

Step-by-step explanation: Distance to school = \frac{7}{10} mile

Distance covered = \frac{5}{8} of \frac{7}{10}

                      = \frac{5}{8} x \frac{7}{10}

                       = \frac{35}{80}

                      = \frac{7}{16}

7 0
2 years ago
What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the
Tasya [4]

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

4 0
4 years ago
Expand and simplify (3a+2)(4a+5)
statuscvo [17]
(3a+2)(4a+5)                  ......expand

12a^2+15a+8a+10         .......group like terms 15a + 8a

12a^2+23a+10               ....this s the answer!
5 0
3 years ago
Read 2 more answers
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