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Tju [1.3M]
3 years ago
7

WHY DOES A MIDI SYSTEM HAVE THE WIDEST RANGE OF FREQUENCIES OUT OF TRUMPET, VIOLIN, PIANO, CLARINET, PIPE ORGAN, KETTLE DRUM AND

A MIDI SYSTEM. YOU GET 15 POINTS
Physics
1 answer:
ICE Princess25 [194]3 years ago
7 0
Each of these instruments have a very wide range of notes because these are all treble instruments. Now, if you mean altogether, with a trumpet you can hit a very wide range of notes due to it having such a high octave, same with a violin, piano, clarinet, and organ. Kettle drums just have a very manipulable sound.
But remember it is a MIDI System, and you can adjust the frequency according to your desire; So, honestly, there is no straight answer for this, just how you desire the sound.

I could take an A4 note on a trumpet and stretch the sound waves out to sound like an A1 note just by bending it with a MIDI System. So, the possibilities are endless.<span />
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When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 44 mi/h\\\\s = 0.00833 mi\\\\=> 0^2 = 44^2 + 2 * a * 0.00833\\\\=> 1936 = -0.01666a\\\\a = -116206.48 mi/h^2 or -14.43 m/s^2

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 79 mi/h\\\\a = -116206.48 mi/h\\\\=> 0^2 = 79^2 + (2 * -116206.48 * s)\\\\6241 = 232412.96s\\\\s = \frac{6241}{232412.96} \\\\s = 0.0268531 mi = 141.78 ft

The minimum stopping distance is 141.78 ft.

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