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3 years ago

10

What is a stock that reinvests its earnings in the business instead of paying regular dividends called?a growth stock , a prefer

red stock, an income stock, a common stock

2 answers:

viva [34]3 years ago

5 0

Answer:

Growths stock

Explanation:

Gradpoint verified

Anastaziya [24]3 years ago

4 0

Answer: growth stock

Explanation:

Gradpoint

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Assume that the Moon is in circular orbit around the Earth. The distance between the Moon and the Earth is approximately 3.56 ×

stira [4]

Answer:

Acceleration = 311.2 Km/hr²

Explanation:

Given: Radius of the Orbit r= 3.56 × 10⁶ km

Period of the orbit = 28 days = 672 hrs

Sol: We have Fc = MV²/r

⇒M ac = MV²/r

⇒ac = V²/r

First we have to Speed V so for this we have to find the circumference ( distance covered by the moon in one orbit)

⇒ Circumference= 2 π r

= 2 × 3.13149 × 3.56 × 10⁶ km

= 22,368,139.69 Km

Now Speed = Distance /time

Speed = 22,368,139.69 Km / 672 hrs

Speed V = 33,285.92 Km/Hr

Now

ac = V²/r = (33,285.92 Km/hrs)² / 3.56 × 10⁶ km

ac = 311.2 Km/hr²

6 0

3 years ago

3. Same questions as the previous problem, but for mass m just falling 3 meters in a vacuum: (a) How long does it take mass m to

sveticcg [70]

Answer:

a) 0.78 s

b) 58.86m/s'

c) Galileo's law of free fall

Explanation:

a) $x = v_{i}t + \frac{1}{2}at^{2} \\3 = 0*t+\frac{1}{2} *9.81*t^{2}\\t=\sqrt{\frac{6}{9.81} }$

b)At the bottom:

kinetic energy = potential energy

$\frac{1}{2}mv^{2} = mgh\\ v^{2} =2*9.81*3=58.86m/s$ downwards

c) Galileo's law of free fall says regardless of the masses, bodies in a vacuum will fall, on the earth, at the same acceleration

3 0

3 years ago

The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. Th

jekas [21]

Answer:

The right solution is "126 Psi".

Explanation:

The given values are:

P₁ = 130 psig

i.e.,

= $130\times 6.894$

= $896.22 \ Kpa$

or,

= $896.22\times 10^3 \ Pa$

Z₂ = 10ft

= 3.05 m

$\delta$ = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒ $\frac{P_1}{\delta_g} +\frac{V_1^2}{2g} +Z_1=\frac{P_2}{\delta_g} +\frac{V_2^2}{2g} +Z_2$

On substituting the values, we get

⇒ $\frac{P_1}{\delta_g} +0+0=\frac{P_2}{\delta_g} +0+Z_2$

⇒ $\frac{896.22\times 10^3}{1000\times 9.8} =\frac{P_2}{1000\times 9.8} +3.05$

⇒ $P_2=866330 \ P_a$

i.e.,

⇒ $=866330\times 0.000145$

⇒ $=126 \ Psi$

8 0

3 years ago

Is it possible for an object with a constant speed to accelerating?

FromTheMoon [43]

Yes. A roulette ball circulating in a spinning wheel, a car going around a curved
road at 30 mph, and a planet in a circular orbit are all being accelerated.

"Acceleration" does NOT mean "speeding up". It means any change in the
speed or DIRECTION of motion.

8 0

3 years ago

Read 2 more answers

At the top of a pole vault, an athlete actually can do work pushing on the pole before releasing it. Suppose the pushing force t

Salsk061 [2.6K]

Answer:

The work done on the athlete is approximately 2.09 J

Explanation:

From the definition of the work done by a variable force:

$\displaystyle{\int_{x_i}^{x_j}F(x)dx}$

and substituting with the function of our problem:

$\displaystyle{\int_{0}^{0.19}(140x-190x^2)dx\approx2.09\mathrm{J}}$

5 0

4 years ago