Answer:
393.399 J/kg.°C
Explanation:
Specific heat capacity: This is the quantity of heat required to raise the temperature of a unit mass of a substance through a degree rise in temperature.
Heat lost by the brass = heat gained by water
CM(t₁-t₃) = cm(t₃-t₂)........................ Equation 1
Where C = specific heat capacity of the brass, M = mass of the brass, t₁ = initial temperature of the brass, t₂ = initial temperature of water, t₃ = temperature of the mixture.
Making C the subject of the equation
C = cm(t₃-t₂)/M(t₁-t₃)............................... Equation 2
Given: M = 0.59 kg, m = 2.8 kg, t₁ = 98 °C, t₂ = 5.0 °C, t₃ = 6.8 °C
Constant: c = 4200 J/kg.°C
Substitute into equation 2,
C = 2.8×4200(6.8-5.0)/0.59(98-6.8)
C = 21168/53.808
C = 393.399 J/kg.°C
Thus the specific heat capacity of the brass = 393.399 J/kg.°C
