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3 years ago

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What are the 2 main parts of physical science

1 answer:

Allisa [31]3 years ago

3 0

Answer:

Physical science is the study of the inorganic world. That is, it does not study living things. (Those are studied in biological, or life, science.) The four main branches of physical science are astronomy, physics, chemistry, and the Earth sciences, which include meteorology and geology.

Explanation:

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At which point does the planet have the least gravitational force acting on it?

Elza [17]

Answer:

At which point does the planet have the least gravitational force acting on it?

Explanation:

In an elliptical orbit, when a planet is at its furthest point from the Sun, it is under the least amount of gravity, meaning that the force of gravity is strongest when it is closest.

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3 years ago

Read 2 more answers

The acceleration of the body in the graph given below is____

Art [367]

Acceleration = -12 / 8 = - .... m/s^2

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3 years ago

Under what conditions might a stream's volume increase, and under what conditions might it decrease? How would the size of the s

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4 years ago

Please solve this asap

brilliants [131]

Let $\vec u$ and $\vec v$ be the vectors, and let $x=\|\vec u\|=\|\vec v\|$ be their common magnitude.

The resultant $\vec u + \vec v$ is $\sqrt 2$ times larger in magnitude than either vector alone, so $\|\vec u+\vec v\| = \sqrt2\,x$ .

Recall the dot product identity

$\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)$

where $\theta$ is the angle between the vectors $\vec a$ and $\vec b$ . In the special case of $\vec a=\vec b$ , we get

$\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}$

Now, to get the angle between $\vec u$ and $\vec v$ , we have

$\vec u \cdot \vec v = \|\vec u\| \|\vec v\| \cos(\theta) \implies \cos(\theta) = \dfrac{\vec u \cdot \vec v}{x^2}$

To compute the dot product, we take the dot product of the resultant with itself.

$(\vec u+\vec v) \cdot (\vec u + \vec v) = \|\vec u + \vec v\|^2$

Solve for $\vec u\cdot\vec v$ .

$(\vec u\cdot\vec u) + 2(\vec u\cdot\vec v) + (\vec v\cdot\vec v) = \|\vec u + \vec v\|^2$

$\|\vec u\|^2 + 2(\vec u\cdot \vec v) + \|\vec v\|^2 = \|\vec u+\vec v\|^2$

$x^2 + 2(\vec u \cdot \vec v) + x^2 = (\sqrt2\,x)^2$

$2(\vec u\cdot\vec v) + 2x^2 = 2x^2$

$2(\vec u\cdot\vec v) = 0$

$\vec u\cdot\vec v = 0$

Since their dot product is zero, $\vec u$ and $\vec v$ are perpendicular, so $\theta=90^\circ$ .

7 0

2 years ago

The AB rope is fixed to the ground at its A end, and forms 30º with the vertical. Its other end is connected to two ropes by mea

lana66690 [7]

Answer:

T = 80√3 N ≈ 139 N

W = 160 N

Explanation:

Sum of forces on B in the x direction:

∑F = ma

80 N sin 60° − T sin 30° = 0

T = 80 N sin 60° / sin 30°

T = 80√3 N

T ≈ 139 N

Sum of forces on B in the y direction:

∑F = ma

80 N cos 60° + T cos 30° − W = 0

W = 80 N cos 60° + T cos 30°

W = 40 N + 120 N

W = 160 N

6 0

3 years ago