1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Keith_Richards [23]
3 years ago
6

What is the density of a substance that has a mass of 453g and a volume of 224mL?

Physics
1 answer:
Mrrafil [7]3 years ago
6 0
Density is mass per unit volume. In this case, the unit is g/ml
Mass=453g                              ρ=453g/224ml
Volume=224ml                         ρ=2.022g/ml(rounded to nearest hundredth)
Density=?
ρ=mass/volume
Therefore the density of the substance is 2.022g/ml

You might be interested in
Select all of the answers that can serve as a meaning for sexuality. (more than one answer may be selected)
Aneli [31]
Gender and self esteem is the answer
5 0
3 years ago
Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is l =  1.0 \ km  =  1000 \  m

       The speed of  A is  v__{A}} =  20 \ m/s

       The uniform acceleration of  B is  a__{B}} =  0.333 \ m/s^2

  Generally the time taken by go-cart  A is mathematically represented as

              t__{A}} = \frac{l}{v__{A}}}

=>          t__{A}} = \frac{1000}{20}

=>           t__{A}} =  50 \  s

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             l =  ut__{B}} + \frac{1}{2}  a__{B}} * t__{B}}^2

given that go-cart B starts from rest  u =  0 m/s

So

            1000 =  0 *t__{B}} + \frac{1}{2}  * 0.333  * t__{B}}^2

=>         1000 =  0 *t__{B}} + \frac{1}{2}  0.333  * t__{B}}^2            

=>         t__{B}} =  77.5 \  seconds  

 

Comparing  t__{A}} \  and  \ t__{B}}  we see that t__{A}} is smaller so go-cart A is  faster

   

       

3 0
2 years ago
When a substance gains electrons, is it positively or negatively charged?
mina [271]

Answer:

negative charge

Explanation:

7 0
2 years ago
In a tug of war, when one team is pulling with a force of 85 N and the other 40 N, what is the net
olya-2409 [2.1K]
85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards
4 0
3 years ago
You own a high speed digital camera that can take a picture every 0.5 seconds. You decide to take a picture every 0.5 seconds of
Vesnalui [34]

-- There is no need to develop the pictures.  They are available immediately in a digital camera.

-- There is no change in the teacher from one picture to the next.

-- The distance the watermelon falls from the teacher in each new picture is more in each picture than in the picture before it. (C)


8 0
2 years ago
Other questions:
  • An object weighs 7.84 N when it is in air and 6.86 N when it is immersed in water of density 1000 kg/m3. What is the density of
    12·1 answer
  • What is the defenition of mass
    10·2 answers
  • Need help with number <br> 50 <br> PLEASE HELP! Show all work please!
    7·1 answer
  • In figure (10), an experiment is set up to find out which metal is the best conductor of heat. Balls are stuck with wax to rods
    13·2 answers
  • In 8,450 seconds, the number of radioactive nuclei decreases to 1/16 of the number present initially. What is the half-life (in
    6·1 answer
  • Rusting metal is an example of a _________ change. A) phase B) state C) chemical D) physical
    15·2 answers
  • Objects accelerate because
    12·1 answer
  • Please helppppppp!!!!!!
    6·1 answer
  • ASAPP PLS HELP MEE
    10·1 answer
  • *WILL MARK BRAINLIEST*
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!