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4 years ago

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Mathematics

1 answer:

sukhopar [10]4 years ago

6 0

Hello! I guess the answer would be C) 20 Days!

Hope I Helped :))

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Find the perimeter of the figure.

Afina-wow [57]

Perimeter
5+5+7+16+7+11 = 51m

7 0

4 years ago

The Length of one side of a parallelogram is 3 more than twice the length of the adjacent side. The perimeter of the parallelogr

katovenus [111]

Answer: 4 cm and 11 cm.

Step-by-step explanation:

1. You can calculate the perimeter of a parallelogram as following:

$P=a+b+c+d$

Where a+b+c+d are the lenghts of the sides.

By definition the parallelogram has two pairs of parallel sides, therefore:

a=c and b=d

Then, you can calculate the perimeter as following:

$P=2(a+b)$

2. Let's call the adjacent side $x$ , then the other side is 2x+3.

3. Substitute values and solve for x:

$30=2(x+2x+3)\\30=2(3x+3)\\30=6x+6\\24=6x\\x=4$

4. Then the lenghts of the sides are:

$x=4cm\\2x+3=2(4cm)+3=11cm$

5 0

4 years ago

Answerr plz who should have possession of the city of Jerusalem, the Jews or the Palestinians?

8_murik_8 [283]

It would be in possession of the Palestinians

7 0

3 years ago

Over what interval is the graph of y=−2 +|x− 2| increasing?

Zepler [3.9K]

Answer:

(2, ∞)

Step-by-step explanation:

An absolute value graph at (0, 0) is an up facing V shape graph. After a few transformation, according to the equation y = −2 + |x− 2|, we have our vertex at (0, - 2). It remains at up facing V graph.

x - h,

x - 2,

x - (+ 2),

h = 2

Therefore our slope is 2, with out vertex at (0, - 2). If we plot our graph, you can see that on the interval (2, ∞) the graph increases...

6 0

4 years ago

Inverse notation f^-1 used In a pure mathematics problem is not always used when finding inverses of applied problems. Rather, t

solong [7]

Answer:

a) 75.4 kg

b) $h(W)=\frac{W+83}{2.2}$

Step-by-step explanation:

a) The ideal weight of a 6-foot (72 inches) male is given by simply applying h= 72 in to the expression:

$W(72) = 49+2.2(72-60)\\W(72) =75.4\ kg$

b) Expressing height as a function of weight:

$W(h)= 49+2.2(h-60)\\2.2h-132+49=W\\h(W)=\frac{W+83}{2.2}$

Verifying with W(h(W)):

$W(h(W))= 49+2.2(\frac{W+83}{2.2} -60)\\W(h(W))= 49-132+W+83\\W(h(W))=W$

Verifying with h(W(h):

$h(W(h))=\frac{(49+2.2(h-60))+83}{2.2}\\h(W(h))=\frac{(49+2.2h-132+83)}{2.2}\\h(W(h))=h$

8 0

3 years ago