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Readme [11.4K]
3 years ago
5

Inverse notation f^-1 used In a pure mathematics problem is not always used when finding inverses of applied problems. Rather, t

he Inverse of a function such as C= C(q) will be q= q(C). The following problem illustrates this idea.
The ideal body weight W for men (in kilograms) as a function of height h (m inches) is given by the following function.

W(h)= 49+2.2(h-60)

Required:
a. What is the ideal weight of a 6-foot male?
b. Express the height h as a function of weight W. Verify your answer by checking that W(h(W)) = W and h(W(h))h.
Mathematics
1 answer:
solong [7]3 years ago
8 0

Answer:

a) 75.4 kg

b) h(W)=\frac{W+83}{2.2}

Step-by-step explanation:

a) The ideal weight of a 6-foot (72 inches) male is given by simply applying h= 72 in to the expression:

W(72) = 49+2.2(72-60)\\W(72) =75.4\ kg

b) Expressing height as a function of weight:

W(h)= 49+2.2(h-60)\\2.2h-132+49=W\\h(W)=\frac{W+83}{2.2}

Verifying with W(h(W)):

W(h(W))= 49+2.2(\frac{W+83}{2.2} -60)\\W(h(W))= 49-132+W+83\\W(h(W))=W

Verifying with h(W(h):

h(W(h))=\frac{(49+2.2(h-60))+83}{2.2}\\h(W(h))=\frac{(49+2.2h-132+83)}{2.2}\\h(W(h))=h

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solniwko [45]
24 ÷12 → 2

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3 years ago
The volume of the rectangular prism is 648 feet. The rectangular base is 6 feet by 9 feet. What is the height of the prism?
IrinaK [193]

Answer:

h=12ft

Step-by-step explanation:

The formula one would use for finding the volume of a rectangular prism is as follows:

  • Volume = length × width × height , V=l*w*h

With this in mind, let's plug in the given variables in the question for this formula.

V=648ft^3

l=6ft

w=9ft

h= ?

  • We don't know the height, but that's just fine. We will plug in all our values and isolate h.

V=lwh\\648ft^3=(6ft)(9ft)h

  • I'm leaving in units just because I want to show that units aren't just for show. They can be used when in doubt of how to go about your math.

648ft^3=(6ft)(9ft)h\\648ft^3=(54ft^2)h\\\frac{648ft^3}{54ft^2}=\frac{(54ft^2)h}{54ft^2}

  • Notice, that the units on the left side cancel out, leaving only the unit ft left next to the solution. In the same way, the units on the right side cancel out too, leaving only h, height.

\frac{648ft^3}{54ft^2}=\frac{(54ft^2)h}{54ft^2}\\12ft=h

If involving units only confuses you, like it does for me, you can remove them like so, you just need to know what units your solution uses instead of being able to come to the proper units by using math.

V=lwh\\648=(6)(9)h\\648=54h\\\frac{648}{54}=\frac{54h}{54}\\12ft=h

5 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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