Answer:

Step-by-step explanation:
Given: Chandler walk 1/16 km every 10 minutes.
First, lets find how many 10 minutes in one hours or convert minutes in hours.
∴ Time= 
Now, finding kilometres travelled in 1 hour.
Distance travelled= 
Distance travelled = 
Converting
into decimal will have 0.375 km.
∴
will chandler walk in 1 hour.
Given: 2<span>√(x - 5) = 2
Taking the square of both sides:
[</span>2√(x - 5) = 2]^2
4(x - 5) = 4
x - 5 = 1
x = 6
Among the choices, the correct answer is A. <span>x = 6, solution is not extraneous .</span>
Answer:

Step-by-step explanation:
<u>Step 1: Determine the equation</u>
So we know that our equation does not have a y-intercept which means that it doesn't intersect ANYWHERE on the y-axis. Therefore, this means that our equation will be a straight vertical line that doesn't move side to side and just goes straight up and down. We also know that our point is (3, 6) which means that our x-value will be 3 and this is where the equation will be located.
There are several ways to display our answer where x = 3 is the most common way which basically means give me all of the y-values for the same x value of 3. Another way of saying it is x - 3 = 0 which either way when adding 3 to both sides gives you x = 3 which is what I usually go with.
Answer: 
George C.
Jul 24, 2018
(
x
+
2
)
(
x
+
6
)
2
=
0
Explanation:
Given:
x
3
+
14
x
2
+
60
x
+
72
=
0
By the rational roots theorem, any rational zeros of the given cubic are expressible in the form
p
q
for integers
p
,
q
with
p
a divisor of the constant term
72
and
q
a divisor of the coefficient
1
of the leading term.
That means that the only possible rational zeros are:
±
1
,
±
2
,
±
3
,
±
4
,
±
6
,
±
8
,
±
9
,
±
12
,
±
18
,
±
24
,
±
36
,
±
72
In addition, note that all of the coefficients are positive and the constant term is non-zero. As a result, any real zero (rational or otherwise) of this cubic must be negative.
So that leaves rational possibilities:
−
1
,
−
2
,
−
3
,
−
4
,
−
6
,
−
8
,
−
9
,
−
12
,
−
18
,
−
24
,
−
36
,
−
72
We find:
(
−
2
)
3
+
14
(
−
2
)
2
+
60
(
−
2
)
+
72
=
−
8
+
56
−
120
+
72
=
0
So
x
=
−
2
is a zero and
(
x
+
2
)
a factor:
x
3
+
14
x
2
+
60
+
72
=
(
x
+
2
)
(
x
2
+
12
x
+
36
)
Without trying any more of our "possible" zeros, we can recognise the remaining quadratic factor as a perfect square trinomial:
x
2
+
12
x
+
36
=
x
2
+
2
(
x
)
(
6
)
+
6
2
=
(
x
+
6
)
2
So the factored form of the given cubic equation can be written:
(
x
+
2
)
(
x
+
6
)
2
=
0
Answer:

Step-by-step explanation:
Given
--- Point
Required
Component of V
From the question, we understand that V is in standard position.
This implies that V starts at the origin (0,0) and ends at (a,b)
So, vector V is:

This gives:

