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Kazeer [188]
3 years ago
15

Solve the inequality and graph the solution set on a number line 200-4.5x less then equal to 20

Mathematics
1 answer:
rodikova [14]3 years ago
3 0

ANSWER

x \geqslant 40

See graph

EXPLANATION

The given inequality is

200 - 4.5x  \leqslant 20

Group like terms.

- 4.5x \leqslant 20 - 200

- 4.5x \leqslant  - 180

Divide both sides by -4.5 and reverse the sign of the inequality.

x \geqslant   \frac{ - 180}{ - 4.5}

x \geqslant 40

See attachment

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Paula walked on the treadmill for 12 minutes. The machine told her she had a total of 780 strides. What was her rate in strides
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4 years ago
All numbers that are between 10 and 20 and give remainder 2 when divided by 3
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5 0
4 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
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