Find the area A of polygon CDEFGH with the given vertices. C(0,5), D(2,5), E(2,3), F(3,2), G(-1,2), H(0,3)
enot [183]
Answer:
<em>The area of the polygon CDEFGH is 7</em>
Step-by-step explanation:
<u>Area of a Polygon</u>
The area of a polygon is generally calculated as the sum of the smaller areas that form its full shape, give each partial area has a known shape, like a square, rectangle, triangle, circle, etc.
The six points given in the question are plotted in the image below. They form a polygon whose area can be divided into two smaller shapes:
The area CDHE is a square of length side 2. Area of a square:
The area HEFG is a trapezoid with bases lengths 4 and 2, and height 1. Area of a trapezoid:
Calculate both areas:
Total Area=4+3=7
The area of the polygon CDEFGH is 7
Answer:
24.0 square feet
Step-by-step explanation:
The area of the sector is given by ...
A = (1/2)r²θ . . . . . where θ is the angle in radians
The area of the circle is the same, with θ=2π, so is ...
A = πr²
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In this problem, the area of the sector is ...
A = (1/2)(9 ft)²(24π/180) = 27π/5 ft² ≈ 16.9646 ft²
The area of the circle is ...
A = π(1.5 ft)² = 9π/4 ft² ≈ 7.0686 ft²
Then the total area of the exclamation point is ...
16.9646 +7.0686 ≈ 24.0 . . . ft²
The area is about 24.0 square feet.
Answer:
write the equation of the line that passes through (7,6) and (-1,2) in a slope intercept form.
Your answer will be x= -4y/3 + 55/3
Answers:
a = 2
b = 3
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Explanation:
Plug in x = 0 and y = 2 to find that
y = a*b^x
2 = a*b^0
2 = a*1
2 = a
a = 2
Then plug in x = 3 and y = 54 to determine the value of b
y = a*b^x
y = 2*b^x
54 = 2*b^3
2b^3 = 54
b^3 = 54/2
b^3 = 27
b = (27)^(1/3)
b = 3
So we have y = a*b^x update to y = 2*3^x
