Ask question

Ask question

All categories

andrezito [222]

3 years ago

12

What kind of weather would an anticyclone likely bring? a. stormy c. dry and clear b. cool and wet d. changeable

2 answers:

RideAnS [48]3 years ago

8 0

By looking at diagrams, My guess is c.
If it helped, it would be appreciated if you can mark as brainliest

yarga [219]3 years ago

5 0

Answer: c. dry and clear

Anticyclone is a drastic weather condition in which winds of high atmospheric pressure blows in a high speed circular pattern. The anticyclone receives it's name due to the flow of wind that is opposed to the Earth rotation. In anticyclone the wind, which is eventually warmer and drier suppresses the cloud formation and thus it prevents the rain. Hence, anticyclone would bring dry and clear weather.

You might be interested in

How long it take a train to cover 630km having a speed of 30 km/hr

noname [10]

Answer:

21 hours

Explanation:

well 30 x 20 = 600 than 21 = 630

4 0

3 years ago

A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$

$\vec v_2=(x_2,y_2)$

The sum of the vectors is:

$\vec v=(x_1+x_2,y_1+y_2)$

The magnitude of a vector can be calculated by

$d=\sqrt{x^2+y^2}$

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

$\vec v_1=(-34,0)$

The wind blows at 19 m/s south, thus:

$\vec v_2=(0,-19)$

The sum of both velocities gives the resultant velocity:

$\vec v =(-34,-19)$

The magnitude of this velocity is:

$d=\sqrt{(-34)^2+(-19)^2}$

$d=\sqrt{1156+361}=\sqrt{1517}$

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0

3 years ago

lana66690 [7]

The answer is A. True

3 0

4 years ago

Read 2 more answers

A long, thin solenoid has 390 turns per meter and a radius of 1.20 cm. The current in the solenoid is increasing at a uniform ra

gtnhenbr [62]

To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.

By definition the induced electromotive force is defined as

$\int E dl = -\frac{d\phi}{dt}$

$\int E dl = -(\frac{dB}{dt})A$

Where,

$\phi =$ Electric field

B = Magnetic Field

A = Area

At the theory the magnetic field is defined as,

$B = \mu_0 NI$

Where,

N = Number of loops

I = current

$\mu_0 =$ Permeability constant

We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then

A = \pi r^2

l = 2\pi r

Replacing at the previous equation we have that

$E (2\pi r) = \mu_0 n (\frac{di}{dt})(\pi R^2)$

Where,

R = Radius of the solenoid

r = The distance from the axis

Re-arrange to find the current in function of time,

$\frac{di}{dt} = \frac{Er}{\mu_0 NR^2}$

Replacing our values we have

$\frac{di}{dt} = \frac{(8.00*10^{-6})(0.0348)}{(4\pi*10^{-7})(390)(1.2*10^-2)^2}$

$\frac{di}{dt} = 3.94487A/s$

8 0

3 years ago

The Milky Way galaxy contains interstellar matter that may a. Form new galaxies b. Form new stars c. Form new universes D. Form

Nana76 [90]

I think the answer is D but I’m not sure

3 0

3 years ago