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Sati [7]
3 years ago
11

How would you find the speed of a ball thrown in to the air- it takes 6 seconds to get tho the top. The height is not given.

Physics
1 answer:
Alecsey [184]3 years ago
7 0
You would need to know how fast you threw the ball in the air once that then multiply the seeped and the time to get your answer<span />
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1
Luda [366]

Explanation:

heat engine is correct answer

3 0
3 years ago
Read 2 more answers
Big Al stands on a skateboard at a rest and throws a 0.5-kilogram rock at a velocity of 10.0 m /sec. Big Al moves back at 0.05 m
Vlada [557]
Let
his and skateboard's combined mass is x
we know
F1=-F2
0.5kg*10m/s=-0.05m/s xkg
5=0.05x(minus cancel with the m/s as it represented the opposite direction of velocity and now there is no velocity in this equation.. so minus is avoidable. and the kgs cancel out)
x=10
so their combined mass is a 100 kg.. (I hope I didn't mess thing up for you)
4 0
3 years ago
Describe the behavior of magnets
tatyana61 [14]
They have a north and South Pole .The opposite poles attract to each other ,the same poles repel from each other.
8 0
3 years ago
A 975-kg elevator accelerates upward at 0.754 m/s2, pulled by a cable of negligible mass. Find the tension force in the cable.
Zina [86]

To solve this problem we will apply the concepts of equilibrium and Newton's second law.

According to the description given, it is under constant ascending acceleration, and the balance of the forces corresponding to the tension of the rope and the weight of the elevator must be equal to said acceleration. So

\sum F = ma

T-mg = ma

Here,

T = Tension

m = Mass

g = Gravitational Acceleration

a = Acceleration (upward)

Rearranging to find T,

T = m(g+a)

T = (975)(9.8+0.754)

T= 10290.15N

Therefore the tension force in the cable is 10290.15N

7 0
3 years ago
The sound from a single source can reach point O by two different paths. One path is 20.0 m long and the second path is 21.0 m l
aleksandrvk [35]

Answer:

minimum frequency = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of sound = 340 m/s

solution

we get here destructive phase that is path difference of minimum \frac{\lambda}{2}

here  λ is the wavelength of the wave

so path difference will be

21 - 20 = \frac{\lambda}{2}  

λ = 2 m

and

velocity that is express as

velocity = frequency × wavelength    .............1

frequency  = \frac{340}{2}  

minimum frequency = 170 Hz

7 0
3 years ago
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