Ask question

Ask question

All categories

snow_tiger [21]

3 years ago

11

A 3.75 bucket of water attached to a rope is swung in a 0.555 m circle. At the bottom, the tension in the rope is 172 N. What is

the speed of the bucket at that point?

1 answer:

julsineya [31]3 years ago

8 0

Idk i meednthenpoints desparetly or ill be stucknon this question for hours with no points to ask

You might be interested in

An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed

Tema [17]

Let the mass of 2500 kg car be $m_1$ and it's velocity be $v_1$ and the mass of 1500 kg car be $m_2$ and it's velocity be $v_2$ .

After the bumping the mass be M and it's velocity be V.

By law of conservation of momentum we have

$m_1v_1+m_2v_2 = MV$

2500 * 5 + 1500 * 1=4000 * V

V = 14000/4000 = 7/2 = 3.5 m/s

So the velocity of the two-car train = 3.5 m/s

9 0

3 years ago

Light intensity is?

Fittoniya [83]

The correct answer is:
<span>The rate at which a waves energy flows through a given unit of area

In fact, light intensity is defined as the light power per unit of area:
</span> $I= \frac{P}{A}$
<span>but the power is the energy carried by the light per unit of time:
</span> $P= \frac{E}{t}$
<span>this means that the intensity can be rewritten as
</span> $I= \frac{E}{tA}$ <span>
So, it's basically the rate of energy (per unit of time) through a given surface.</span>

5 0

3 years ago

Read 2 more answers

A car drives 20 miles north and then 3 miles south. what is the displacement or the car

kobusy [5.1K]

An:
Displacement is 16.

5 0

3 years ago

Read 2 more answers

HELLO , PLZ HELP .

sergey [27]

Answer:

the pressure due to the water on the diver is 200,000 pascal

pressure = height × density × acceleration due to gravity

p = 20×1000×10

p=200,000 pascal

6 0

3 years ago

A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object i

guapka [62]

(a) If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b) if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

$\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}$

(a)

when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

$\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)$

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

$\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)$

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

Learn more here:brainly.com/question/19887955

3 0

2 years ago