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Varvara68 [4.7K]
3 years ago
8

Solve the system be either substitution or elimination 3x-5y=21 and 2x+y=1

Mathematics
2 answers:
hram777 [196]3 years ago
6 0

Answer:

x = 2, y = -3.

Step-by-step explanation:

3x - 5y = 21

2x + y = 1

We can use elimination by first multiply the second equation by 5:-

10x + 5y = 5  Now add this to the first equation:-

13x = 26

x = 2.

Now plug x = 2 anto the second equation to find y:-

2(2) + y = 1

y = 1 - 4 = -3.

IRISSAK [1]3 years ago
4 0

Answer:

(2,-3)

Step-by-step explanation:

I used substitution and rearranged the second equation to y=-2x+1. Then I replaced the y in the first equation with -2x+1. So, I got 3x-5(-2x+1)=21. When you solve that you get 13x=26 or x=2. Then you replace x with 2 in either equation and end up with y=-3.

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