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Varvara68 [4.7K]
3 years ago
8

Solve the system be either substitution or elimination 3x-5y=21 and 2x+y=1

Mathematics
2 answers:
hram777 [196]3 years ago
6 0

Answer:

x = 2, y = -3.

Step-by-step explanation:

3x - 5y = 21

2x + y = 1

We can use elimination by first multiply the second equation by 5:-

10x + 5y = 5  Now add this to the first equation:-

13x = 26

x = 2.

Now plug x = 2 anto the second equation to find y:-

2(2) + y = 1

y = 1 - 4 = -3.

IRISSAK [1]3 years ago
4 0

Answer:

(2,-3)

Step-by-step explanation:

I used substitution and rearranged the second equation to y=-2x+1. Then I replaced the y in the first equation with -2x+1. So, I got 3x-5(-2x+1)=21. When you solve that you get 13x=26 or x=2. Then you replace x with 2 in either equation and end up with y=-3.

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When solving an equation with an absolute value term, you make two separate equations ans solve for x:

Equation 1: |4x-3|-5 = 4

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|4x-3| = 9

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4x-3 = 9 and 4x - 3 = -9

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When you replace x with those values in the original equation the statement is true so those are two solutions.

Do the same thing for equation 2:

|2x+3| +8 = 3

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2x +3 = -5

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The answer is:

C. The solutions to equation 1 are x = 3, −1.5, and equation 2 has no solution.

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