14* 6=84 , sorry for the delay enjoy your day!
W=2L-5
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A=L*W
=L(2L-5)
=2L²-5L
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dA/dL=4L-5
When dA/dL=0,
4L-5=0
4L=5
L=5/4
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When L=5/4
A=5/4*(2*(5/4)-5)
=5/4*(10/4-20/4)
=5/4*((-10)/4)
=5/4*(-5/2)
=-25/8
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*You may have been given a badly written out question. The answer doesn't make sense.
The area formula for a rectangle is A = L*W. We have the area as 3197, now we just have to find a way to directly relate the length to the width with only one unknown, since we can't have 2 unknowns. The problem tells us that the length is 22 in. less than 7xW. That will be expressed as L=7W-22, and width is just W. Filling in we have 3197=W(7W-22). Distributing through the parenthesis we have
. Since we have to solve for x and the only way we can do that is by factoring, we will move the 3197 over to the other side by subtraction and then factor the quadratic.
. I recommend putting that into the quadratic formula, and when you do you get W values of 23 and -19.857 The only 2 things in math that will never EVER be negative are time and distance/length. And since one of our lengths there is negative we know that that is not the one we will use. Therefore, the width is 23. The length then is L=7(23)-22 which is 139
To find the answer, take 52 x 0.75 which should be 39
Answer:
x^3 - 2x^2 + 9x - 18.
Step-by-step explanation:
The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.
So we have:
P(x) = (x - 2)(x - 3i)(x + 3i)
= (x - 2)(x^2 - 9i^2)
= (x - 2)(x^2 - 9*-1)
= (x - 2)(x^2 + 9)
= x^3 + 9x - 2x^2 - 18
= x^3 - 2x^2 + 9x - 18.