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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
7.5
Step-by-step explanation:
Divide 30 by 3.99
Answer:
he sold 4 boxes of cookies and 3 chocolate bars
Step-by-step explanation:
5+5+5+5 = 20 3+3+3 = 9 so add 20+9 = 29
I think x equals 54
Hope this helps
Answer:
The 90% confidence interval for the population mean iron concentration is between 0.167 cc/m³ and 0.195 cc/m³.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 0.181 - 0.0140 = 0.167 cc/m³.
The upper end of the interval is the sample mean added to M. So it is 0.181 + 0.0140 = 0.195 cc/m³.
The 90% confidence interval for the population mean iron concentration is between 0.167 cc/m³ and 0.195 cc/m³.
