keeping in mind that radius is half the diameter, we know this cone has a diameter of 2 inches, so it has a radius of 1 inch, kinda small really for ice-cream, but anyhow.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=1\\ h=6 \end{cases}\implies V=\cfrac{\pi (1)^26}{3}\implies V=2\pi \implies \underset{\textit{rounded up}}{V\approx 6}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D1%5C%5C%20h%3D6%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%281%29%5E26%7D%7B3%7D%5Cimplies%20V%3D2%5Cpi%20%5Cimplies%20%5Cunderset%7B%5Ctextit%7Brounded%20up%7D%7D%7BV%5Capprox%206%7D)
Step-by-step explanation:
11. shape 1 => A = ½×17×10=85m²
shape 2=> A = 17×9 =153 m²
total area = 238 m²
12. shape 1 => A = 7×3= 21 m²
shape 2=> A = 3×2 = 6 m²
total area = 27 m²
Answer:
36 ft by 16 ft
Step-by-step explanation:
To solve this problem, you need to find dimensions of a rectangle such that the perimeter is 104 ft and the area is 576 ft. The perimeter is twice the sum of length and width, so the sum of length and width is 52 ft.
The area is the product of length and width, so if w represents the width, we have ...
w(52 -w) = 576
w² -52w = -576 . . . . . eliminate parentheses, multiply by -1
w² -52w +26² = 26² -576 . . . . . . complete the square
(w -26)² = 676 -576 = 100
w = 26 ±√100 = {16, 36}
If the width is the short dimension, it is 16 feet. Then the length is 36 feet.
Step-by-step explanation:
to find height :
draw a height from A to CD
height = (13) 2 - 5) 2 = 12 Cm
area = 10+20 /2 X 12= 180 cm 2
<u><em>Answer:</em></u>
<u><em>4(2+7)=16</em></u>
<u><em>The answer is:</em></u>
<u><em>36=16</em></u>
<u><em>or</em></u>
<u><em>A</em></u>
<u><em>Hope this helps:3</em></u>
<u><em /></u>
