We are given the function
F(x) = 9 sinx + cot x
We need to take the first derivative of the given function so,
F' (x) = 9 cos x - csc² x
Next, we equate the first derivative of the function to 0 and solve for the values of x
0 = 9 cos x - csc² x
Solving for x
x = 2.04
Picking out an arbitrary value between 2.04 and π, say 3 and substituting in F(x)
F(3) = 9 sin 3 + cot 3 = 19.55
Therefore, the interval where the function is increasing is from 2.04 to π
Consequently, the interval where the function is decreasing is from -π to 2.04<span />
Answer:
ez
Step-by-step explanation:
Answer:
-49x - 18 is the final answer!
Answer:
2n*m. when there is a one in front of a letter, it is immediately just the letter
It would be A. 2.28 x 10^9
You don’t multiply exponents you only add them for now
