Answer:
c = 169
Step-by-step explanation:
We can use FOIL to determine this after factoring out the equation.
(x+13)(x+13)
F: (x*x)
O: (x*13)
I: (13*x)
L: (13*13)
x^2 + 26x + 169
10^10 = 100
20^2 = 400
29^29 = 841
28^28 = 784
I think it is 8,4 let me now if it is right
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
