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vichka [17]
3 years ago
6

What is the value of the expression below when p=1/8? 16p-10

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0
The answer is -8.

16p - 10

16(1/8) - 10

16(0.125) - 10

2 - 10 = -8
Orlov [11]3 years ago
6 0
Replace 1/8 into the equation for p and you get 2 - 10 which is -8
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Please help
lubasha [3.4K]

Let us check series : -10 /-2 = 5 -50/-10 = 5

so it is a geometric series with a= -2 and r= 5

sum formula for n terms of geometric series = a ( r^n -1 ) /( r-1)

here we find S5 that is n= 5 = -2 ( 5^ 5 - 1) /( 5-1)

= -2 ( 3125 -1) / 4 = -1562

second series is : 1.5/1 = 1.5 2.25/1.5 = 1.5

this is also geometric series but n = 12 a= 1 and r= 1.5

we use same formula

S12 = 1 ( (1.5) ^12 -1) /( 1.5-1) =

128.74 / 0.5 = 257.49

Last is 2/1= 2 4/2 = 2 8/4 = 2 so r = 2 a = 1 and n = 12

we use same formula 1 ( 2^12 - 1) / (2-1)

= 4095

Answers : -1562 , 257.49 , 4095

8 0
3 years ago
Read 2 more answers
PLS help<br><br> 44-9+77 divided by 8=
Andrews [41]

Answer:

14

Step-by-step explanation:

44-9=35

35+77=122

122÷8=14

6 0
2 years ago
Read 2 more answers
Please sleep me helpppp
defon

Answer:

help me first on this question

Step-by-step explanation:

5 0
3 years ago
Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)
yuradex [85]

Answer:

b.  \frac{x+3}{x-1}

Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

Let us factorize the numerator using the formula:

a^{2} -b^{2} =(a+b)(a-b)

\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, \frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}

7 0
4 years ago
Is the proportion 28/16 = 14/8 correct
horsena [70]

Answer:

yes

Step-by-step explanation:

its correct because divide by 2/ 28/16=14/8

maybe

5 0
3 years ago
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