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vichka [17]
3 years ago
6

What is the value of the expression below when p=1/8? 16p-10

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0
The answer is -8.

16p - 10

16(1/8) - 10

16(0.125) - 10

2 - 10 = -8
Orlov [11]3 years ago
6 0
Replace 1/8 into the equation for p and you get 2 - 10 which is -8
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Find the solution of the system of equations.<br>6x + 8y = -8<br>x + 4y = 4<br>( , )​
ladessa [460]

Answer:

the solution is (-4, 2)

Step-by-step explanation:

6x + 8y = -8

x + 4y = 4

... can be solved using elimination by addition and subtraction, among other methods.  Multiply the second equation by -2 to obtain

6x + 8y = -8

-2x - 8y = -8

Combining these results in

4x = -16.  Thus, x = -4.

Substituting -4 for x in x + 4y = 4 results in

-4 + 4y = 4, or 4y = 8, or y = 2

Then the solution is (-4, 2)

8 0
3 years ago
PLS HELP I NeED to finish this
mote1985 [20]

Answer:

D. 15

Step-by-step explanation:

<em>Use proportions.</em>

<em />\frac{35}{25} = \frac{21}{x}  \\\\35x = 525\\x = 15<em />

3 0
3 years ago
Step by step 7 ,9, and 11 please. EVEN IF U CANT DO ALL, u can help with 1 or 2. Ill mark brainly.
gregori [183]

Answer:

7) 4 \ log_3(x) - 4 \ log_3(y)

9) 5log_4(7) - 5log_4(12)

11) 5log_5 \ (x) - log_5 \ (y)

Step-by-step explanation:

log_3 (\frac{x}{y})^{4}

----------------------------------------------------------------------------------------------------

Use Logarithm of a Quotient which states

log_b \frac{M}{N}  = log_b M-log_bN

And also use Logarithm of a Power which states

log_b\ M^{n} = n\log_bM

----------------------------------------------------------------------------------------------------

So using these two properties,

7. 4 \ log_3(x) - 4 \ log_3(y)

----------------------------------------------------------------------------------------------------

----------------------------------------------------------------------------------------------------

For #9, use the same logarithm propertied

log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)

----------------------------------------------------------------------------------------------------

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#11 is also the same concept

log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)

It is not  - 5 log5(y) since only x is to the power of 5 not y

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Hope this is what you were looking for and helps you! Have a nice day/night :)

5 0
3 years ago
Lisa reads 1/2 of a 200 page book
alexgriva [62]

Answer: 24 days

Step-by-step explanation:

Takes her 4 days to read 1/2 of a 200 page book, or 100 pages.

4 days = 100 pages

X days = 600 pages

24 days = 600 pages

6 0
3 years ago
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard devi
kotykmax [81]

Answer:

0.35% of students from this school earn scores that satisfy the admission requirement.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.

This means that \mu = 1479, \sigma = 302

The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?

The proportion is 1 subtracted by the pvalue of Z when X = 2294. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2294 - 1479}{302}

Z = 2.7

Z = 2.7 has a pvalue of 0.9965

1 - 0.9965 = 0.0035

0.0035*100% = 0.35%

0.35% of students from this school earn scores that satisfy the admission requirement.

6 0
3 years ago
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