a class collects 54 pounds of food each holiday food drive how many 6 pound bags can the class collect

Which table represents a linear function?

solniwko [45]

Answer:

C.

Step-by-step explanation:

1 -3

2 -5

3 -7

4 -9

Because it has a constant slope it is increasing x by 1 and decreasing y by -2.

Slope: -2/1 or -2x

3 0

2 years ago

Read 2 more answers

Which expression could be substituted for y in the second equation to find the value of x?

AlexFokin [52]

Answer:

x = 31 /4 , y = −11 /2

8 0

2 years ago

Show that in a group of five people (where any two people are either friends or enemies), there are not necessarily three mutual

sveta [45]

Answer:

Lets call the people A,B,C,D and E. We need to find an example where there are not 3 mutual friends and not three mutual enemies.

Lets start by assuming that A has 2 friends, B and C, and 2 enemies, D and E.

Since we want A,B and C not to be mutually friends, then B and C neccesarily have to be enemies.

Now, since B and C are enemies, they cant be enemies at the same time with D, and they also cant be enemies at the same time with E. Therefore one of them has to be friends with D and one has to be friends with E.

Also, since D and E are enemies with A, they neccesarily need to be friends.

From the fact that D and E are friends, we coclude that they cant have a friend in common, as a consequence, B has to be friends with one of D and E and C has to be friend with the other. We can assume that B is friend with D and C is friend with E. If we use that, we have the following friendship configuration

---------------------

Friends of A: B, C

Enemies of A: D,E

-------------------------

Friends of B: A,D

Enemies of B: C, E

------------------------

Friends of C: A,E

Enemies of C: B,D

------------------------

Friends of D: B,E

Enemies of D: A,C

----------------------------

Friends of E: C,D

Enemies of E: A,B

--------------------------

As you can check, there is not three mutual friends nor three mutual enemies.

8 0

2 years ago

The surface area of the figure is?

MissTica

The answer would be C

6 0

2 years ago

Karen gave an equal amount of m and m's to herself and four friends. Each person receives m and m's equivalent to the largest on

Mariana [72]

Answer:

Karen had 45 m and m's candy.

Step-by-step explanation:

Let the number of m and m's candy be 'x'.

Now given:

Karen gave an equal amount of m and m's to herself and four friends.

So we can say that;

Number of people m and m's candy distributed equally = 5

Also Given:

Each person receives m and m's equivalent to the largest one digit number.

Now we know that;

Largest one digit number is 9.

So we can say that;

Each person receives m and m's = 9

We need to find number of m and m's Karen have.

Solution:

So we can say that;

Total number of m and m's Karen have is equal to Number of people m and m's candy distributed equally multiplied by number of m and m's can each person receives.

framing in equation form we get;

Total number of m and m's Karen had = $9\times5 = 45$

Hence Karen had 45 m and m's candy.

8 0

2 years ago