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motikmotik
2 years ago
13

The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreci

ation, and t = time, in years. A car was purchased 6 years ago for $25,000. If the annual depreciation rate is 11%, which equation can be used to determine the approximate current value of the car?.
Mathematics
1 answer:
nlexa [21]2 years ago
4 0

The equation which is used to determine the approximate current value of the car by the depreciation equation is,

y=25000(0.89)^6

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

y=A\left(1-{r}\right)^t

Here,(y) is the current value, (A) is the original cost of the product, (r) is the rate of depreciation and (t) is the number of years.

Now the car was purchased 6 years ago. The original cost of the car is $25,000 and the annual depreciation rate is 11%.
The rate can be given as,

r=\dfrac{11}{100}\\r=0.11

Thus, to find the equation can be used to determine the approximate current value of the car, put the values in the above formula as,

y=(25000)\left(1-{0.11}\right)^6\\y=25000(0.89)^6

Hence, the equation which is used to determine the approximate current value of the car by the depreciation equation is,

y=25000(0.89)^6

Learn more about the depreciation here;

brainly.com/question/25297296

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Answer:

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b) 58.65% of heights between 160 centimeters and 180 centimeters

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 162, \sigma = 8

a) The percentage of heights less than 150 centimeters

We have to find the pvalue of Z when X = 150. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{150 - 162}{8}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

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b) The percentage of heights between 160 centimeters and 180 centimeters

We have to find the pvalue of Z when X = 180 subtracted by the pvalue of Z when X = 160.

X = 180

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Z = \frac{180 - 162}{8}

Z = 2.25

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X = 160

Z = \frac{X - \mu}{\sigma}

Z = \frac{160 - 162}{8}

Z = -0.25

Z = -0.25 has a pvalue of 0.4013

0.9878 - 0.4013 = 0.5865

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