Ask question

Ask question

All categories

3 years ago

5

Some reports claim that the Dunkin' Donuts chain sells 950 million donuts in five months. At this rate, how many donuts would Th

e chain of shops so in one year?

2 answers:

Lorico [155]3 years ago

8 0

950/5=190
190*12=2280

2 billion and 280 million or 2.28 billion

uysha [10]3 years ago

3 0

950/5=190
190×12=2280
2.28 billions

You might be interested in

Which<br> expression is equivalent to -3-4

Bess [88]

Answer: wheres the photo ?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Ken has 8 apples in his

Marat540 [252]

Answer:10

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

4. Lupe knows that there are 4 quarts in a gallon. She wants to convert 6 quarts to gallons, but cannot decide if she should mul

tangare [24]

Answer:

Step-by-step explanation:

4 quarts=1 gallon

1 quart=1/4 gallon

6 quarts 1/4×6=6/4 gallons=3/2 gallons =1 1/2 gallons

or we can say 4 quarts=1 gallon

2 quarts=1/2 gallon

(4+2=6)quarts=(1+1/2)=1 1/2 gallon.

3 0

3 years ago

Can you use the SSS Postulate or the SAS Postulate to prove triangle FEZ is congruent to triangle FGZ?

love history [14]

SAS only. The 3rd side cannot be proven.

8 0

3 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago