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NeTakaya
3 years ago
5

Some reports claim that the Dunkin' Donuts chain sells 950 million donuts in five months. At this rate, how many donuts would Th

e chain of shops so in one year?
Mathematics
2 answers:
Lorico [155]3 years ago
8 0
950/5=190
190*12=2280

2 billion and 280 million or 2.28 billion
uysha [10]3 years ago
3 0

950/5=190
190×12=2280
2.28 billions
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I was wondering what is 9/2 divided by 1/2
liubo4ka [24]

Answer:

\frac{18}{2} or 9

Step-by-step explanation:

1. Set up the problem: \frac{9}{2} ÷ \frac{1}{2}

2. Replace the division sign with a multiplication sign: \frac{9}{2} × \frac{1}{2}

3. Find the reciprocal by swapping the numerator and denominator on the second fraction:  \frac{9}{2} × \frac{2}{1}

4. Multiply fractions:  \frac{9}{2} × \frac{2}{1} = \frac{18}{2} or 9

6 0
3 years ago
Which expression is equivalent to:1/m6
Valentin [98]

Answer:

A

Step-by-step explanation:

6 is a power. So both C and D are wrong because 6 is being treated as an ordinary integer.

So the answer must be either A or B.

B is not correct because to move an expression from the denominator to the numerator changes the sign in the base (which is m in this  question).

A is correct. the power is changed from 6 in the denominator to -6 in the numerator. m is shifted to the numerator as well.

8 0
3 years ago
Least Common factor 37 and 14
Musya8 [376]

Answer:

2 and 7

Step-by-step explanation:

14:    2 7  

37:        37

LCM:    2 7 37

The Least Common Multiple (LCM) is:   2 x 7 x 37 = 518

8 0
3 years ago
Read 2 more answers
A tank with a capacity of 500 gal originally contains 200 gal of water with 100 lb of salt in solution. Water containing 1 lb of
saw5 [17]

Let A(t) denote the amount of salt in the tank at time t.

Salt flows in at a rate of

(1 lb/gal) * (3 gal/min) = 3 lb/min

and flows out at a rate of

(A(t)/(200 + t) lb/gal) * (2 gal/min) = 2 A(t)/(500 + t)

(in case you're unsure about the denominator: the tank starts off with 200 gal of solution, and each minute solution flows in at a rate of 3 gal/min and thus the tank gains (3 gal/min) * (1 min) = 3 gal. At the same time, solution flows out at a rate of 2 gal/min and thus the tank loses 2 gal, giving a net change in volume of (3 - 2)*t = t gal)

Then the net rate of salt flow is given by the ODE,

\dfrac{\mathrm dA(t)}{\mathrm dt}-\dfrac{2A(t)}{200+t}=3

Multiply both sides by (200+t)^{-2}:

(200+t)^{-1}\dfrac{\mathrm dA(t)}{\mathrm dt}-2(200+t)^{-3}A()=3(200+t)^{-2}

\implies\dfrac{\mathrm d}{\mathrm dt}\bigg((200+t)^{-2}A(t)\bigg)=3(200+t)^{-2}

Integrating both sides and solving for A(t) gives

(200+t)^{-2}A(t)=-\dfrac3{200+t}+C

A(t)=-2(200+t)+C(200+t)^2

The tank starts off with 100 lb of salt in solution, so A(0)=100 and we find

100=-2(200)+C(200)^2\implies C=\dfrac1{80}

and so

A(t)=-2(200+t)+\dfrac{(200+t)^2}{80}=\dfrac{(200+t)(40+t)}{80}

The tank will begin to overflow once the volume of solution reaches 500 gal; this happens when

500=200+t\implies t=300

or 300 minutes or 5 hours after solution starts flowing. At this point, the tank will contain

A(300)=2125

or 2125 lb of salt.

Theoretically, the amount of salt in the tank will increase forever, since A(t)\to\infty as t\to\infty.

6 0
4 years ago
Which pair of expressions is equivalent?
Diano4ka-milaya [45]

Answer:

D

Step-by-step explanation:

7(1–k)

= 1(7) -k(7)  -------------> distributive property

= 7–7k

3 0
3 years ago
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