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Dafna11 [192]
3 years ago
14

Which percent is eguivalent to 2.5? 1)2.5% 2)25% 3)250% 4)2,500%

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0

Answer: 250%

since, 100% = 100/100

250% = 250/100

Step-by-step explanation:

slava [35]3 years ago
3 0
I believe the answer is 250%, percent is usually out of 100 so 2.5•100=250%
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Dan's science magazine has a mass of 256.674 grams. What is the mass of his magazine rounded to the nearest tenth
notka56 [123]
The mass is 256.7 because you round it up from 7.
5 0
3 years ago
A 40 meter ladder makes an angle of 32° with the playground. How far is the bottom of the ladder from the base of the playground
postnew [5]

Answer:

33.9 m

Step-by-step explanation:

cos(32) = adjacent/hypotenuse

cos(32) = X/40

X = 40cos(32)

X = 33.92192385 m

4 0
4 years ago
3/12 irrational or rational number
mash [69]
3/12=1/4 simplified and in decimal form it is .25 so it is RATIONAL because it ends. A rational number is any number that can be put into a form of a/B and B doesn't equal zero
3 0
3 years ago
Read 2 more answers
If the radius of a sphere is increasing at the constant rate of 3 centimeters per second, how fast is the volume changing when t
kotykmax [81]

How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.

To solve the question, we need to know the volume of a sphere

<h3>Volume of a sphere</h3>

The volume of a sphere V = 4πr³/3 where r = radius of sphere.

<h3>How fast the volume of the sphere is changing</h3>

To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.

So, dV/dt = d(4πr³/3)/dt

= d(4πr³/3)/dr × dr/dt

= 4πr²dr/dt where

  • dr/dt = rate of change of radius of sphere and
  • 4πr² = surface area of sphere

Given that

  • dr/dt = + 3 cm/s (positive since it is increasing) and
  • 4πr² = surface area of sphere = 10 cm²,

Substituting the values of the variables into the equation, we have

dV/dt = 4πr²dr/dt

dV/dt = 10 cm² × 3 cm/s

dV/dt = 30 cm³/s

So, how fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.

Learn more about how fast volume of sphere is changing here:

brainly.com/question/25814490

7 0
2 years ago
Find all values of c such that 3^2c+1=28*3^c-9. If you find more than one value of c, then list your values in increasing order​
avanturin [10]

3^{2c} + 1 = 28\times3^c - 9 \implies 3^{2c} - 28\times3^c = -10

Complete the square on the left side:

3^{2c} - 28\times3^c = \left(3^{2c}-28\times3^c+14^2\right)-14^2 = \left(3^c-14\right)^2 - 196

Then the equation becomes

\left(3^c-14\right)^2 - 196 = -10 \\\\ \left(3^c-14\right)^2 = 186 \\\\ 3^c - 14 = \pm\sqrt{186} \\\\ 3^c = 14\pm\sqrt{186}

Both 14 + √186 and 14 - √186 are positive numbers, so we can take the logarithm (base 3) of both sides without issue:

\log_3\left(3^c) = c = \log_3\left(14\pm\sqrt{186}\right)

Then in increasing order, the solutions are

<em>c</em> = log₃(14 - √186), <em>c</em> = log₃(14 + √186)

3 0
3 years ago
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