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3 years ago

A cone has height h and a base with radius r. You want to change the cone so its

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

3 0

9514 1404 393

Answer:

a) h/2

b) r/√2 = (r√2)/2

Step-by-step explanation:

a) The volume of a cone is proportional to height. If the volume is halved, then the height will be halved.

The new height will be h/2.

b) The volume is proportional to the square of the radius. If the volume is halved, the square of the radius is halved. The new radius will be ...

(r')² = r²/2

r' = r/√2 = (r√2)/2 . . . radius of half-volume cone

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3 years ago

The rectangle below has an area of 1 8 x 3 18x 3 square meters and a length of 2 x 2 2x 2 meters.

motikmotik

Answer:

$\text{The width of rectangle}=9x\text{ meters}$

Step-by-step explanation:

We have been given that the rectangle has an area of $18x^3$ square meters and a length of $2x^{2}$ . We are asked to find the width of rectangle.

Since we know that area of a rectangle is width times length of the rectangle, so we can find width of our given rectangle by dividing given area by length of rectangle.

$\text{Area of rectangle}=\text{Width of rectangle *Length of the rectangle}$

$\frac{\text{Area of rectangle}}{\text{Length of rectangle}}=\frac{\text{Width of rectangle *Length of the rectangle}}{\text{Legth of rectangle}}$

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Upon substituting our given values in above formula we will get,

$\text{The width of rectangle}=\frac{18x^3\text{ meter}^2}{2x^2\text{ meters}}$

$\text{The width of rectangle}=\frac{9x^3\text{ meters}}{x^2}$

Using exponent rule for quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

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