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3 years ago

7

one of the heaviest ranfalls recorded in greentown in a 24-hour period was 178.8 centimeters. If the ranfall was constant, how m

any centimeters of rain fell during each hour?

1 answer:

Ilya [14]3 years ago

6 0

There will be 7.45 centimeters of rain fell during each hour.

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You decided to throw a fair die four times.

Finger [1]

Answer:

If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.

the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).

Step-by-step explanation:

7 0

2 years ago

"at the end of the year Juan has $52.71 more than 4 times his balance at the beginning of the year if his ending balance was $17

Salsk061 [2.6K]

At the end of the year, Juan has 52.71 more than 4 times his balance at the beginning. Okay, let's set this up.

4x + 52.71
(4 times) (52.71 more)
His ending was 172.90, so
4x + 52.71=172.90
4x= 120.19
x= 30.05
He had $30.05 at the beginning of the year.

8 0

4 years ago

A firm buys components from two suppliers: 60 percent from supplier A and the rest from supplier B. It so happens that 9 percent

Llana [10]

Answer:

0.114,0.5263

Step-by-step explanation:

Given that a firm buys components from two suppliers:

A : 60% Defective 9%

B:40% Defective 15%

a) the probability that the next component the firm buys is defective

=prob purchased from A and defective + prob purchased from B and defective

= $0.60(0.09)+0.40(0.15)\\= 0.054+0.06\\=0.114$

b) the probability that the component that the firm buys is from supplier B if we know that it is defective

=Prob from B and defective/Prob defective

= $\frac{0.40(0.15)}{0.114} \\=0.5263$

8 0

3 years ago

A company has a policy making the compensation of its CEO proportional to the dividends that are paid to shareholders. If the di

Serggg [28]

Well... looking at proportions, we're being asked $\bf \cfrac{72}{360000}=\cfrac{80}{420000}\impliedby \textit{are those proportions the same?}$

3 0

3 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

3 years ago