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chubhunter [2.5K]
3 years ago
7

Which statement is true about this argument ?

Mathematics
2 answers:
MrRa [10]3 years ago
5 0
D the argument is not valid because the conclusion does not follow from the premises
nignag [31]3 years ago
5 0
It's good to review the laws of syllogism and detachment.

Law of detachment:
Statement 1: If p then q.
Statement 2: p is true.
By the law of detachment, you can conclude "q is true."

Law of syllogism:
Statement 1: If p then q.
Statement 2: If q then r.
By the law of syllogism, you can conclude "If p then r."

Now look at which of the two cases above you have.
Statement 1: If a quadrilateral is a square, then the quadrilateral is a rectangle.
This is "if p then q."

Statement 2:
<span>If a quadrilateral is a rectangle then the quadrilateral is a parallelogram.
This is "if q then r."

You have
If p then q.
If q then r.

This is what you need for the law of syllogism.

That means you can conclude "if p then r", which in this specific case is
"</span><span>If a quadrilateral is a square, then the quadrilateral is a parallelogram."
</span>
The answer is that it is a valid argument by the law of syllogism.
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If w+ -4 2/5= 1/10 what does w equal
Nesterboy [21]

Answer:

Step-by-step explanation:

w+ -4 2/5= 1/10

W = 1/10 + 4 2/5

W = 1/10 + 22/5

W = (1 + 44)/10

W = 45/10

W = 9/2

W = 4 1/2

8 0
3 years ago
Factor by GCF
madam [21]

Answer:

10x^(2)-4x

Step-by-step explanation:

8 0
3 years ago
Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0
3 years ago
Read 2 more answers
2) 3x + 4y = 8<br> 2x+y=42<br> a) (30, -19)<br> b) (31, -20)<br> c) (32,-22)<br> What is the answer
kirza4 [7]

Answer:

C

Step-by-step explanation:

We can solve simultaneous equations using substitution method, elimination method or graphical method. But for this purpose, we will be using the elimination method.

3x+4y=8 Equation 1

2x+y=42 Equation 2

Multiply Equation 1 by 2 and equation 2 by 3, so as to get the same coefficient for x

2(3x+4y=8)= 6x+8y=16 Equation 3

3(2x+y=42)= 6x+3y=126 Equation 4

Subtract equation 4 from 3, to eliminate x

6x-6x=0

8y-3y= 5y

16-126= -110

We now have 5y=-110

Divide both sides by 5,

y= -110/5

= -22

Substituting for y in equation 2

2x+(-22)= 42

2x= 42+22

2x=64

x= 64/2

= 32

(x, y)

(32, -22)

7 0
3 years ago
Solve this system of linear equations. Separate
Katyanochek1 [597]

Answer:

good question

Step-by-step explanation:

5 0
3 years ago
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