Answer:
that is the answer which you ask me
Help with math problem
1 answer:
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Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = = 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
Answer:
(C) 220
Step-by-step explanation:
Let x represent the number of adult tickets sold and y represent the number of student tickets sold. With the information given, we can set up two equations:
(Since for every adult ticket sold, $5 is made and for every student ticket sold, $3 is made)
In the first equation, we can represent x in terms of y:
And then, we can substitute x in the second equation for 360 - y to get:
which simplifies to:
and therefore,
.
Hope this helps :)