Solve for Y when x = 1:
y = log5 (1)
Y = 0
Solve for X when Y = 1
1 = log5 x
X = 5
The graph that includes the two points (1,0) and (5,1) is B.
Answer:
8.37 minutes
Step-by-step explanation:
The key word times helps us know what operation we're doing, which is multiplication. Multiply 9.3 by 0.9 to get your answer.
Step-by-step explanation:
you would take how munch the price for one is and times it by 5
She has 6 on Wednesday
Since we know that she has 4/9 left, 4/9 of 27 is 12. So she has 12 on Tuesday. Now 2/4 or 1/2 is left on Wednesday. Half of 12 is 6. So she has 6 left
Answer:
Option (A) and (C).
Step-by-step explanation:
Prime polynomial can't be written as a product of lower degree polynomials.
(A)
![8x^2-10x-3](https://tex.z-dn.net/?f=8x%5E2-10x-3)
=8x²-6x-4x-3
=2x(4x-3)-1(4x+3)
Here we can't write the polynomial as a product of lower degree.
Therefore it is a prime polynomial.
(B)
8x²+2x-3
=8x²+6x-4x-3
=2x(4x+3)-1(4x+3)
=(4x+3)(2x-1)
Therefore it is not a prime polynomial.
(C)
8x²-6x-3
Therefore it is a prime polynomial.
(D)
8x²+23x-3
=8x²+24x-x-3
=8x(x+3)-1(x+3)
=(x+3)(8x-1)
Therefore it is not a prime polynomial.