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4 years ago

Can someone please write out the decimal 4.014 as a fraction? (There’s no need to simplify/reduce the fraction either)

Mathematics

1 answer:

Svetradugi [14.3K]4 years ago

6 0

Answer:

4014/1000

Step-by-step explanation:

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What is the value of x? Round the answer to the nearest tenth. The diagram is not drawn to scale.

pshichka [43]

X = 50

Reason: Chord AB and Chord CD are equal.

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3 years ago

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If sinθ = 12/13 and θ is an acute angle, find cotθ.

Tju [1.3M]

Answer:

cot(θ)=5/12

Step-by-step explanation:

(I'm going to replace theta with x to save time.)

Recall that sine is equal to opposite over hypotenuse. Thus:

sin(x)=12/13, this means that the opposite side is 12 while the hypotenuse is 13 (well, it doesn't have to be, but their ratios are).

Find the adjacent side using the Pythagorean Theorem.

13^2 = 12^2 + adj^2

adj^2 = 25

adj = 5.

Recall that tan(x) is opposite over adjacent. This means that cot(x) is adjacent is opposite.

Therefore: cot(x) = 5/12.

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4 years ago

The diameter of a water molecule is about 0.0000003 millimeters, which can be written as 3x10^n millimeters. What is n?

pishuonlain [190]

Answer:

n = - 7

Step-by-step explanation:

$0.0000003 = 3 \times {10}^{ - 7} \\ \implies \: n \: = - 7$

8 0

4 years ago

Write an equation that has the given solutions. 1, -1

shutvik [7]

Answer:

(x+1)(x-1)

Step-by-step explanation:

The solutions 1 and - 1 is given when

x = 1 or x = - 1

hence; (x - 1) = 0 or (x + 1) = 0

(x - 1)(x + 1) = 0

x² -1 = 0

Mark as brainliest answer please. Thanks

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2 years ago

Suppose you want to decrease your margin of error by a factor of 3. by what factor, do you need to increase your sample size? in

elena55 [62]

The sample size, n required to produce a margin of error, M, in a probability proportion distribution is given by:

$n= \frac{p(1-p)z_{\alpha/2}^2}{M^2}$

The above formular shows that the sample size is inversely proportional to the Margin of error.

Then we have:

$n= \frac{k}{M^2}$

where k is some constant.

Now suppose we decrease M by a factor of 3,

$\left(i.e.\ \frac{M_1}{M_2} =3\right)$

$n_1= \frac{k}{M_1^2} \\ \\ n_2= \frac{k}{M_2^2} \\ \\ \frac{n_2}{n_1} = \frac{k}{M_2^2} / \frac{k}{M_1^2} = \frac{k}{M_2^2} \times \frac{M_1^2}{k} = \frac{M_1^2}{M^2_2} =\left( \frac{M_1}{M_2} \right)^2=3^2=9 \\ \\ n_2=9n_1$

Therefore, if we decrease the Margin of error by a factor of 3, we need to increase the sample size by a factor of 9.

6 0

4 years ago