Answer:
It's the last choice: 2x^2 - 5x - 8 - 37/(x - 5).
Step-by-step explanation:
Long division:
2x^2 - 5x -8 <---------------Quotient
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x - 5 ) 2x^3 - 15x^2 + 17x + 3
2x^3 - 10x^2
- 5x^2 + 17x
- 5x^2 + 25x
- 8x + 3
- 8x + 40
-37 <------ Remainder.
Answers:
- a) 15000 represents the starting amount
- b) The decay rate is 16%, which means the car loses 16% of its value each year.
- c) x is the number of years
- d) f(x) is the value of the car after x years have gone by
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Explanation:
We have the function f(x) = 15000(0.84)^x. If we plug in x = 0, then we get,
f(x) = 15000(0.84)^x
f(0) = 15000(0.84)^0
f(0) = 15000(1)
f(0) = 15000
In the third step, I used the idea that any nonzero value to the power of 0 is always 1. The rule is x^0 = 1 for any nonzero x.
So that's how we get the initial value of the car. The car started off at $15,000.
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The growth or decay rate depends entirely on the base of the exponential, which is 0.84; compare it to 1+r and we see that 1+r = 0.84 solves to r = -0.16 which converts to -16%. The negative indicates the value is going down each year. So we have 16% decay or the value is going down 16% per year.
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The value of x is the number of years. In the first section, x = 0 represented year 0 or the starting year. If x = 1, then one full year has passed by. For x = 2, we have two full years pass by, and so on.
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The value of f(x) is the value of the car after x years have gone by. We found that f(x) = 15000 when x = 0. In other words, at the start the car is worth $15,000. Plugging in other x values leads to other f(x) values. For example, if x = 2, then you should find that f(x) = 10584. This means the car is worth $10,584 after two years.
<span>I think this is the answer cos 30=<span><span>3–√</span>2</span></span>
Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
Answer:
see attached image
Step-by-step explanation:
F(x) = 2x + 5 is a linear graph because the exponent on x is 1. I tell my students that think of graphs having one less turn/corner that the value of the highest exponent. so since 2x has a exponent of 1, 1-1 =0 so it has no turns or its a straight line.
this has a slope of 2 or 2/1 or up 2 and right 1 from the y intercept which is 5
so mark 5 on the y axis and a from there go up 2 and right 1 and make another point. Join these points and you have your graph
and
g(x) = (x-5)/2 is its inverse and is found:
F(x) = 2x + 5 write it this way y = 2x + 5
now swap the x and y x = 2y - 5
solve for y
x = 2y + 5
- 5 -5
x - 5 = 2y
/2 /2
(x-5)/2 = y
it can be written as y = x/2 - 5/2
and graphed the same way as above with a 1/2 slope and -5/2 y intercept
