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andreev551 [17]
3 years ago
5

Solve for x. (x - 4)(x - 4) = 0 a.-16 b. -4 c. 4 d. 16

Mathematics
2 answers:
DerKrebs [107]3 years ago
3 0

(x - 4)(x - 4)=0. Then, (x - 4)=0 and (x - 4) =0.

In both cases, x is 4. Thus, you have a double real root: {4, 4}.

monitta3 years ago
3 0

Answer:

7

Step-by-step explanation:

x - 4 =  

16 - x

(x - 4)2 = 16 - x

x2 - 8x + 16 = 16 - x

-x2 + 7x = 0

-(x(x - 7)) = 0

multiple both sides by -1:

x(x - 7) = 0

x = 0 or x = 7

Check solutions:

x = 7 ⇒

7 - 4 =  

16 - 7

3 =  

9

3 = 3

x = 7 is a solution

x = 0 ⇒

0 - 4 =  

16 - 0

-4 =  

16

-4 ≠ 4

x = 0 is not a solution (extraneous root)

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3 years ago
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andrey2020 [161]

Answer:

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Step-by-step explanation:

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6 0
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Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.
Oksanka [162]

Answer:

Option (1)

Step-by-step explanation:

x               -2              -1                 0                    1                   2

y               10            2.5                0                  2.5                3.0

Ist difference,

d_1=y_2-y_1

    =2.5-10=-7.5

d_2=y_3-y_2

    =0-2.5

    = -2.5

d_3=y_4-y_3

    =2.5-0

    = 2.5

d_4=y_5-y_4

    =10.0-2.5

    = 7.5

2nd difference,

x_1=d_2-d_1

    =-2.5+7.5

    = 5

x_2=d_3-d_2

    =2.5+2.5

    = 5

x_3=d_4-d_3

    =7.5-2.5

    = 5

Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

2.5 = a(1)² + b(1)

a + b = 2.5 ------(2)

By adding equations (1) and (2),

2a = 5

a = 2.5

and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

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Answer:

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Step-by-step explanation:

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