Solve for x. (x - 4)(x - 4) = 0 a.-16 b. -4 c. 4 d. 16
2 answers:
(x - 4)(x - 4)=0. Then, (x - 4)=0 and (x - 4) =0.
In both cases, x is 4. Thus, you have a double real root: {4, 4}.
Answer:
7
Step-by-step explanation:
x - 4 =
16 - x
(x - 4)2 = 16 - x
x2 - 8x + 16 = 16 - x
-x2 + 7x = 0
-(x(x - 7)) = 0
multiple both sides by -1:
x(x - 7) = 0
x = 0 or x = 7
Check solutions:
x = 7 ⇒
7 - 4 =
16 - 7
3 =
9
3 = 3
x = 7 is a solution
x = 0 ⇒
0 - 4 =
16 - 0
-4 =
16
-4 ≠ 4
x = 0 is not a solution (extraneous root)
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