The marginal distribution for gender tells you the probability that a randomly selected person taken from this sample is either male or female, regardless of their blood type.
In this case, we have total sample size of 714 people. Of these, 379 are male and 335 are female. Then the marginal probability mass function would be
![\mathrm{Pr}[G = g] = \begin{cases} \dfrac{379}{714} \approx 0.5308 & \text{if }g = \text{male} \\\\ \dfrac{335}{714} \approx 0.4692 & \text{if } g = \text{female} \\\\ 0 & \text{otherwise} \end{cases}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BG%20%3D%20g%5D%20%3D%20%5Cbegin%7Bcases%7D%20%5Cdfrac%7B379%7D%7B714%7D%20%5Capprox%200.5308%20%26%20%5Ctext%7Bif%20%7Dg%20%3D%20%5Ctext%7Bmale%7D%20%5C%5C%5C%5C%20%5Cdfrac%7B335%7D%7B714%7D%20%5Capprox%200.4692%20%26%20%5Ctext%7Bif%20%7D%20g%20%3D%20%5Ctext%7Bfemale%7D%20%5C%5C%5C%5C%200%20%26%20%5Ctext%7Botherwise%7D%20%5Cend%7Bcases%7D)
where G is a random variable taking on one of two values (male or female).
I’m going to say b.66 because 3.14•10.5•2=65.94
I got 10.5 by dividing 21 by 2 because I guessed it was the diameter
Answer:
i believe its 21.5
Step-by-step explanation:
Answer:
The probability is;
0.0000003645
Step-by-step explanation:
The probability of packages being early p is 90% = 0.9
The probability of packages being late q will be 1-p = 1-0.9 = 0.1
So the probability of 2 out of 10 random late will be subject to Bernoulli approximation of the Binomial theorem
That will be;
P(X = 2) = 10 C 2 0.9^2 0.1^8
= 0.0000003645
The first one is y=4x+-11. The second one is y=-5/2x+2
