Answer:
Yes
Step-by-step explanation:
In order to determine if a triple of values will form a triangle, we must apply the Triangle Inequality Theorem, which states that for a triangle with lengths a, b, and c:
a + b > c
a + c > b
b + c > a
Here, let's suppose that since the ratio of the sides is 3 : 4 : 5, then let the actual side lengths be 3x, 4x, and 5x, where x is simply a real value.
With loss of generality, set a = 3x, b = 4x, and c = 5x. Plug these into the Triangle Inequality to check:
a + b > c ⇒ 3x + 4x >? 5x ⇒ 7x > 5x ⇒ This is true
a + c > b ⇒ 3x + 5x >? 4x ⇒ 8x > 4x ⇒ This is also true
b + c > a ⇒ 4x + 5x >? 3x ⇒ 9x > 3x ⇒ This is true
Since all three conditions are satisfied, we know that a true triangle can be formed given that the ratio of their sides is 3 : 4 : 5.
<em>~ an aesthetics lover</em>
Let me tell you....
This equation cannot be solved at all.
Why?
3(n+5)≥3n+8
3n+15 ≥ 3n+8
3n-3n ≥ 8-15
0 ≥ -7
Even though it make sense than 0 ≥ -7... But since 'n' disappeared, this means that this equation have no solution. To solve means to find the value of 'n' and if there is no 'n' since 3n-3n=0, there is no solutions.
This question is pretty much invalid.
Extra:
To tackle such inequality qns:
Step 1: Expand the brackets
Step 2: Move the term to one side of the equations
and constant to another side of the equation.
Step 3: Find the value of the term. Done.
