Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Answer:
Step-by-step explanation:
245.000......same as 245....rounded to nearest hundred = 200
9514 1404 393
Answer:
6.2 ft
Step-by-step explanation:
The volume of a cylinder is given by ...
V = πr²h
Here, we have r=2h and V=3000 ft³. Putting these numbers into the formula and solving for h, we get ...
3000 ft³ = π(2h)²h
(3000 ft³)/(4π) = h³ . . . . . divide by the coefficient of h³
h = ∛(750/π) ft ≈ 6.2 ft
The pool is about 6.2 feet deep.
Answer:
Step-by-step explanatin
it affects it because your going from smaller tires witch make it easier to make turns go faster things like that when you put bigger tires on the car it is gonna raise the car and have a whole differnt outlook
The first bubble is the answer