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elixir [45]
3 years ago
11

PLEASE HELPBRAINLIEST AVAILABLE THXPLEASE ASSIST ME N TRY TO HELP ME

Mathematics
1 answer:
GaryK [48]3 years ago
5 0
D is the answer


hope i helped
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3x – 15y = 12<br> 2x - 10y = 8<br><br><br> What is the ordered pair?
katrin [286]
The answer should be 9,1
5 0
3 years ago
1/3 divided by 4 someone help!!
kozerog [31]

Answer:

1/12

Step-by-step explanation:

1/3 x1/4=1/12

6 0
3 years ago
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Write the equation for function g(x)
iragen [17]

Answer:

g(x) = (x + 2)^2 + 1

Step-by-step explanation:

From the graph/image that you have provided said translated shift of

f(x) -> g(x)

f(x) = x^2 , g(x) = a(x -h)^2 +k

h is shift right/left

k is shift up/down.

It appears that the shift is left 2 and up 1.

h = -2 and k = 1

g(x) = (x - (-2))^2 +1

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5 0
2 years ago
The sequence {an} is defined by a0 = 1 and
zavuch27 [327]
The solution to the problem is as follows:

Just plug in the numbers and follow the pattern. 

a0 = 1 

a1 = 2*1 + 2 = 4 

a2 = 2*4 +2 = 10 

<span>a3 = 2*10 +2 = 22
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I hope my answer has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
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A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
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