6 - 1/2z = 2/3
Steps
First, subtract 6 from both sides
6 - 1/2z - 6 = 2/3 - 6
Then, simplify
-1/2z = -16/3
Then, multiply both sides by -2
(-1/2z) (-2) = (-16/3) (-2)
Then, simplify
z = 32/3
<span>6.4u−5.1u=−3.25
Simplify
1.3u = -3.25
Divide both sides by 1.3
1.3u/1.3 = -3.25/1.3
Simplify
u = -2.5</span>
Step-by-step explanation:
1. b + 2
2. x - 2
3. 2z
4. a ÷ 2
5. y^2
The third one hope this helps
Given that the terminal side of an <θ intersects the unit circle at the point
![P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})](https://tex.z-dn.net/?f=P%28%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%29)
From the given point P:
![\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%20%5C%5C%20%5Ctext%7B%20s%7Dince%2C%5Ctext%7B%20x%20is%20positive%20and%20y%20is%20negative%2C%20the%20angle%20lies%20in%20the%204th%20quadrant%7D%20%5Cend%7Bgathered%7D)