We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer <span>
considering the case N 2 </span>
isvertex (4,-1)------> is correcty intercept (0,-17)-----> is correctaxis of symmetry x=4-----> is correct
2xy + 5 - 8 + 3xy - y +7 + 3y = 5xy - 8 + 2y + 12
Answer:
a=-6
Step-by-step explanation:
4= 6/a + 5
Subtract 5 from each side
4-5= 6/a + 5 -5
-1 = 6/a
Multiply by a on each side
-1*a = 6/a *a
-a =6
Multiply by -1
a= -6
Answer:
$60.00
Step-by-step explanation:
you subtract the original number with the new number to see the difference.