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3 years ago

11

A group of 5 students are running a relay race. If the race is 1/4 of a mile long and each student runs the same distance how fa

r does each student need to run

2 answers:

abruzzese [7]3 years ago

6 0

1/20 mile. divide 1/4 by 5 by fliping the division sign and 5. (1/4)(1/5)=1/20

pashok25 [27]3 years ago

3 0

1/20 is your answer hope I got it right

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The perimeter of △CDE is 55 cm. A rhombus DMFN is inscribed in this triangle so that vertices M, F, and N lie on the sides CD ,

tamaranim1 [39]

Answer:

CD=20 cm and DE=15 cm. CD=20 cm and DE=15 cm.

Step-by-step explanation:

A rhombus DMFN is inscribed in such a way that it is inscribed in triangle CDE with the vertices M, F, and N l on the sides CD , CE , and DE respectively.

Now, in rhombus, the parallel sides are always parallel, therefore

MF║DE, thus, $\frac{CM}{MD}=\frac{CF}{EF}$ by the basic proportionality condition.

It is given that CF=8 cm and EF=12 cm, therefore, $\frac{CM}{MD}=\frac{8}{12}$ .

That is CM=8 cm and MD=12 cm. Therefore, CD=CM+MD=8+12=20.

According to question, Perimeter of △CDE =55 cm

⇒CD+DE+CE=55

⇒20+DE+20=55

⇒DE=15 cm

Hence, CD=20 cm and DE=15 cm.

8 0

4 years ago

Read 2 more answers

If one atom of carbon weighs 1.99 × 10^−22 g and one atom of hydrogen weighs 1.67 × 10^−27 g, which element weighs more? Explain

garik1379 [7]

Answer:

The atom of carbon weighs more

Step-by-step explanation:

we have

<em>Atom of carbon weighs</em>

$1.99*10^{-22}\ g=1.99*10^{-22}(\frac{10^{5}}{10^{5}})=199,000*10^{-22}(\frac{1}{10^{5}})=199,000*10^{-27}\ g$

<em>Atom of hydrogen weighs</em>

$1.67*10^{-27}\ g$

Compare

$199,000*10^{-27}\ g > 1.67*10^{-27}\ g$

therefore

The atom of carbon weighs more

8 0

3 years ago

What is 60% of 64, please idk know this lol

marshall27 [118]

Its 38.4 because i am big brain

3 0

3 years ago

Read 2 more answers

I need help on this. The portrait studio can buy photographs on canvas. The small canvas photograph print is $20 and the large c

Whitepunk [10]

<h3>Answer:</h3>

6 large prints
12 small prints

<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

... 2×$20 +45 = $85

To have revenue of at least $510, the studio must sell ...

... $510/$85 = 6

sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.

_____

<em>With an equation</em>

Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...

... 20·2x +45·x ≥ 510

... 85x ≥ 510

... x ≥ 510/85

... x ≥ 6

The studio needs to sell at least 6 large prints and 12 small prints.

8 0

3 years ago

Jake completed a marathon race in 3 hours and 12 minutes. What would be Jake's running time as a decimal?

VikaD [51]

$\text{Given that Jake completed a marathon race in 3 hours and 12 minutes.}\\
\\
\text{we need to find this time in decimals. so we will convert 12 minutes into hours}\\
\\
\text{We know that there are 60 minutes in 1 hour. }\\
\\
\text{so in 1 minute there will be}=\frac{1}{60 }\text{ hour}$

$\text{hence in 12 minutes we have}=\frac{1}{60}\times 12=\frac{1}{5}=0.2 \text{ hours}\\
\\
\text{hence the Jake's running time is}=3\text{hours + 12 minute}\\
\\
=3\text{ hours}+0.2 \text{ hours}\\
\\
=3.2 \text{ hours}$

Hence, Jake's running time in decimal is: 3.2 hours

4 0

3 years ago