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padilas [110]
3 years ago
13

What is the product of the 2 solutions of the equation x^2+3x-21=0

Mathematics
1 answer:
Advocard [28]3 years ago
3 0
X²+3x-21=0

1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2

2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21

Answer: the product of the 2 solutions of this equation is -21
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The difference is 7x^{2}  + 1x-7.

Step-by-step explanation:

Step 1:

The polynomial -5x^{2}+3x+8 is subtracted from the polynomial 2x^{2} + 4x +1.

If we write this as an equation, we get

(2x^{2} + 4x +1) -(-5x^{2}+3x+8).

To subtract the polynomials, we group up the terms based on their variables.

In this subtraction, there are two variables i.e. x^{2} and x and there is one constant term.

Step 2:

The subtraction of the x^{2} variables; 2x^{2}  -(-5x^{2} )  = 2x^{2} +5x^{2} = 7x^{2}.

The subtraction of the x variables; 4x - (3x) = 1x.

The subtraction of the constants; 1-(8) = -7.

So (2x^{2} + 4x +1) -(-5x^{2}+3x+8) = 7x^{2}  + 1x-7.

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3 years ago
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Agata [3.3K]

Start by combining the fractions:

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\dfrac{2\cos\alpha}{1-\sin^2\alpha}

Recall the Pythagorean identity:

\dfrac{2\cos\alpha}{\cos^2\alpha}

Then cancel a factor of \cos\alpha and use the definition of secant:

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<h3>Then we have the answer:</h3>

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