Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is
.
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as 
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
3 1/2r=28
3.5r=28
cross of 3.5 and r remains
divide 28 and 3.5
and r=8
r=8
Answer:
(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed ⇒ 3rd answer
Step-by-step explanation:
Let us revise some rules of exponents
×
=
×÷
= 
= 
=
. 
To simplify 
∵ 5t means 5 × t
∵ Both of them are cubed
- Use the 4th rule above
∴
= 
∵ (5)³ = 5 × 5 × 5 = 125
∴
=
= 125 t³
(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed
Answer: We should reject the null if the test statistic is greater than <u>1.895</u>.
Step-by-step explanation:
We assume the population to be normally distributed.
Given: Sample size :
, which is asmall sample (n<30), so we use t-test.
We always reject the null hypothesis if the absolute t-value is greater than critical value.
Therefore, We should reject the null if the test statistic is greater than <u>1.895</u>.