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umka2103 [35]
3 years ago
5

What is the mathematical answer for -15-15-15-13?

Mathematics
2 answers:
zysi [14]3 years ago
7 0
-58...................….........?.???????
RUDIKE [14]3 years ago
7 0
Your answer would be -58
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Which athletes, if any, would qualify for the finals if the length of a jump that qualifies for the finals were at least 20 feet
saul85 [17]

Answer:

Amir and ryan would qualifiey

Step-by-step explanation:

5 0
2 years ago
The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe
alexgriva [62]
Let the width be x.

Length is 8 feet more than width. Length = x + 8

Area = x(x + 8)

width increased by 4, that is,  (x + 4)
Length decreased by 5,    (x + 8 - 5) = (x + 3)

Area  = (x + 4)(x +3)

Area remains the same

x(x + 8) = (x+4)(x +3)

x² + 8x =   x(x +3) + 4(x +3)

 x² + 8x =   x² +3x + 4x +12

x² + 8x =   x² +7x +12        Eliminate x² from both sides

8x = 7x + 12

8x - 7x = 12

x = 12

Dimensions of original rectangle :  x,  x + 8

12, 12 +8 =   12, 20

Original rectangle is   20 feet   by 12 feet 
5 0
3 years ago
Read 2 more answers
2. What is the measure of angle AOE and angle EOD?<br><br> X+138<br><br> x + 48
horrorfan [7]

Answer:

AOE = 138, EOD = 48

Step-by-step explanation:

Since AD is the diameter of the circle and goes through the middle

angle AOE + angle EOD  = 180

Solving the equation (x + 138) + ( x+ 48) = 180

We get x = 0.

8 0
2 years ago
HELP WITH THIS QUESTION PLEASE!!
svetlana [45]

m<PQS = m<SQR

4y - 10 = 2y + 10

2y = 20

y = 10

m<PQR = m<PQS + m<SQR

= 4y - 10 + 2y + 10

= 6y

= 6•10

= 60

3 0
3 years ago
1. A five-number summary of a univariate data set is determined to be [10, 15, 25, 45, 85]. These data are to be used to constru
kompoz [17]

Answer:

A) I only

Step-by-step explanation:

median = 25

mean = 36

Plot for given distribution is shown in fig attached below. mean is shown with red block and median with green block. plot is skewed to the left and there is no outlier.

3 0
3 years ago
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