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Leni [432]
3 years ago
9

A bag of fertilizer covers 3000 square feet of lawn. Find how many bags of fertilizer should be purchased to cover a rectangular

lawn 230 feet by 180 feet
Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

14 bags

Step-by-step explanation:

Dimension of lawn : 230 feet by 180 feet

area of rectangle is given by length * width

Since lawn is rectangular area of lawn = 230 feet * 180 feet = 41,400 sq. feet

Given that one bag of fertilizer covers 3000 square feet of lawn.

Thus , to find no. of bags required to cover whole lawn will be

total area of lawn/area which one bag of  fertilizer covers

no. of bags required to cover whole lawn = 41,400 sq. feet/3000 sq. feet

    = 13.8 bags.

As no. of bags cannot be fractional , hence rounding bag to nearest unit place is 14 bags.

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397 students went on a field trip. Eight
lbvjy [14]

Answer:48

Step-by-step explanation:

Total number of students=397

Students that travelled in a car=29

Let the students that travelled in a bus be represented by y.

Since 8 buses were filled, it will be 8y for total students

8y + 29= 397

8y= 397-29

8y= 368

Divide both side by 8

8y/8=368/8

y = 46

Number of students in each bus is 46

8 0
3 years ago
What is the area and perimeter for 107 cm
belka [17]
it would be 15 in 2
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What is a unit of area with dimensions 1 unit times 1 unit
ycow [4]
1 \text{ u} \cdot 1 \text{ u}=1 \text{ u}^2
5 0
3 years ago
What is the missing term in the factorization?<br><br> 18x2−32=2(3x+?)(3x−4)
Nataly_w [17]
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2(9x^2 - 16) =
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5 0
3 years ago
Suppose that in a senior college class of 500500 ​students, it is found that 179179 ​smoke, 228228 drink alcoholic​ beverages, 1
olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16

b) eats between meals and drink alcohol but does not smoke.

P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058

c) neither smokes nor eats between meals.

P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0
2 years ago
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