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anyanavicka [17]
3 years ago
9

Write a problem that the expression 3(-7) - 10 + 25 = -6 could represent

Mathematics
1 answer:
noname [10]3 years ago
3 0
-21-10+25=-6
-6=-6

its true
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Roll three dice A, B and C together. What is the probability that the numbers on A, B, C are strictly increasing or decreasing?
Artemon [7]

Answer:

The Probability of strictly increasing or decreasing order is 20/216

Step-by-step explanation:

First Die           1    2    3     4   5   6

Second Die     1    2    3     4   5   6

Third Die         1    2    3     4   5   6

Total number of outcomes= 6*6*6= 216

Possible outcomes of increasing order

1,2,3-----1,2,6  (4)

1,3,4------1,3,6 (3)

1,4,5------1,4,6 (2)

1,5,6 (1)

2,3,4—-2,4,6 (3)

2,4,5—-2,4,6 (2)

2,5,6 (1)

3,4,5—-3,4,6 (2)

3,5,6 (1)

4,5,6 (1)

Total number of possible moves of increasing order= 4+3+2+1+3+2+1+2+1+1= 20

Probability of strictly increasing order is 20/216

Similarly Probability of strictly decreasing order is calculated which is also equal to 20/216

3 0
4 years ago
What is a + a^2 ?<br> Thank you<br> Don't write the steps, just the answer
Natalka [10]
Oh okie so cute lol lol is
7 0
3 years ago
Which is a cubic function?
dexar [7]

Answer:

c

Step-by-step explanation:

because it is to the third power

3 0
4 years ago
Read 2 more answers
Yes, by sss <br> Yes, by sas<br> Yes, by asa <br> Yes, by aas<br> Not enough info
Montano1993 [528]

Answer:um

Step-by-step explanation:

4 0
3 years ago
Five thousand dollars is deposited into a savings account at 2.5% interest compounded continuously.
Mumz [18]

Answer:

A). A(t) = P(1+r/n)^(nt)

B). DA/Dt = np(1+r/n)^(t)

C). A(5) =$ 5664.0

D).t = approximately 13.5 years

Step-by-step explanation:

A(t) = P(1+r/n)^(nt)

P = $5000

n= t

r= 2.5%

After five years t = 5

A(t) = P(1+r/n)^(nt)

A(5) = 5000(1+0.025/5)^(5*5)

A(5) = 5000(1+0.005)^(25)

A(5)= 5000(1.005)^(25)

A(5) = 5000(1.132795575)

A(5) = 5663.977875

A(5) =$ 5664.0

When the balance A= $7000

A(t) = P(1+r/n)^(nt)

7000= 5000(1+0.025/n)^(nt)

But n= t

7000= 5000(1+0.025/t)^(t²)

7000/5000= (1+0.025/t)^(t²)

1.4= (1+0.025/t)^(t²)

Using trial and error

t = approximately 13.5 years

8 0
3 years ago
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